Question

第一篇文章，并且只学习Python 3周......

我正在尝试创建一个游戏，其中2个玩家必须等待连接到面包板的蜂鸣声，然后按下按钮以查看谁是第一个。

这很好，直到我尝试添加一种保持分数的方法。现在，当游戏运行时，按下按钮时蜂鸣器不会停止，我会在窗口中看到几条重复的错误消息。任何人都可以帮我看看我做错了吗？

from gpiozero import Button, LED, Buzzer
from time import time, sleep
from random import randint

led1 = LED(17)
led2 = LED(27)
btn1 = Button(14)
btn2 = Button(15)
buz = Buzzer(22)
score1 = 0
score2 = 0

btn1_name = input('right player name is ')
btn2_name = input('left player name is ')

while True:
    print(btn1_name + ' ' + str(score1) + ' - ' + btn2_name + ' ' + str(score2))
    sleep(randint(1,10))
    buz.on()
    def pressed(button):
        if button.pin.number == 14:
            print(btn1_name + ' won the game')
            score1 += 1
        else:
            print(btn2_name + ' won the game')
            score2 += 1
        buz.off()
    btn1.when_pressed = pressed
    btn2.when_pressed = pressed

输出消息如下

dave 0 - keith 0
keith won the game
Traceback (most recent call last):
  File "/usr/local/lib/python3.4/dist-packages/gpiozero/pins/rpigpio.py", line 232, in <lambda>
    callback=lambda channel: self._when_changed(),
  File "/usr/local/lib/python3.4/dist-packages/gpiozero/mixins.py", line 311, in _fire_events
    self._fire_activated()
  File "/usr/local/lib/python3.4/dist-packages/gpiozero/mixins.py", line 343, in _fire_activated
    super(HoldMixin, self)._fire_activated()
  File "/usr/local/lib/python3.4/dist-packages/gpiozero/mixins.py", line 289, in _fire_activated
    self.when_activated()
  File "/usr/local/lib/python3.4/dist-packages/gpiozero/mixins.py", line 279, in wrapper
    return fn(self)
  File "/home/d.chilver/twobuttonreaction.py", line 26, in pressed
    score2 += 1
UnboundLocalError: local variable 'score2' referenced before assignment
dave 0 - keith 0

Answer 1

问题是范围界定的问题。两个变量<table id="table"> <thead> <tr> <th data-field="state" data-checkbox="true"></th> <th data-field="name">Name</th> <th data-field="stargazers_count">Stars</th> <th data-field="forks_count">Forks</th> </tr> </thead> </table> JSON temp.json { "Name": "Julie own", "Account": "C0010", "LoanApproved": "12/5/2015", "LastActivity": "4/1/2016", "PledgedPortfolio": "1000000", "MaxApprovedLoanAmt": "1000000", "LoanBalance": "1849000", "AvailableCredit": "201877.824375", "Aging": "3", "Brokerage": "My Broker", "Contact": "R Johnson", "ContactPhone": "-3614", "RiskCategory": "Yellow", "rows": [{ "Account": "086-1234", "ClientName": "Sal Smith", "AccountType": "Ret", "LongMarketValue": "$450000" }, { "Account": "086-1235", "ClientName": "y Smith", "AccountType": "Trust", "LongMarketValue": "$550000" }, { "Account": "086-1236", "ClientName": "y Smith", "AccountType": "Retail", "LongMarketValue": "$550000" }] }和score1位于所谓的全局范围内。但是你想在函数中本地使用它们。 Python尝试通过分配局部变量score2或score1然后添加1来分别创建一个名为score2或score1的局部变量。由于该变量尚不存在，受到您看到的错误消息。

要访问全局变量，您必须明确标记它们：

score2

两个按钮反应游戏使用python3和覆盆子pi3

1 个答案: