我正在编写一个可以访问数据库的休息服务,以查看,添加和更新mysql表中的字段。我用Spring Boot实现了这个。
事实是,当我尝试自动装配DAO对象时它不起作用,为null,所以我的应用程序总是抛出NullPointerException。
这是我的应用程序类:
@SpringBootApplication
@EnableSwagger2
@ComponentScan(basePackages = "com.setoncios.api")
@EnableJpaRepositories("com.setoncios.api.dao.workers.WorkerDAO.java")
public class GenericApiApplication {
public static void main(String[] args) {
SpringApplication.run(GenericApiApplication.class, args);
}
@Bean
public Docket swaggerSettings() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build()
.pathMapping("/");
}
这是我的pom.xml:
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-jdbc</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>com.google.code.gson</groupId>
<artifactId>gson</artifactId>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger-ui</artifactId>
<version>2.6.1</version>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger2</artifactId>
<version>2.6.1</version>
</dependency>
</dependencies>
这是我的DAO实现:
@Component
public interface WorkerDAO extends CrudRepository<Persona,String>{
}
包含抛出异常的方法的rest方法:
@RequestMapping(value = "/worker", method = RequestMethod.POST)
public ResponseEntity<?> addWorkerInDatabase(HttpServletRequest request,
@RequestParam(value = "json", defaultValue =
"{\"dni\":\"00000000A\",\"nombre\":\"Paco\",\"apellido1\":\"Ruiz\",\"apellido2\":\"Díaz\"}") final String json){
ProcessAction object = new AddWorkerInDatabaseAction(request, json);
return object.createResponse();
}
班级本身:
public class AddWorkerInDatabaseAction extends ProcessAction{
private String json;
@Autowired
private UserDatabase userDb = new UserDatabase();
@Autowired
private WorkerDAO workDb;
public AddWorkerInDatabaseAction(HttpServletRequest request, String json) {
super(request);
this.json = json;
}
@Override
protected Object action() throws ExpectedException {
Persona newWorker = new Gson().fromJson(json, Persona.class);
Cookie c = findCookie("userdata");
String[] loggedUser = null;
if(newWorker == null){
LOGGER.warning("Unable to decrypt from json to Persona.");
} else if(c == null){
LOGGER.info("Couldn't find cookie. Unable to add a worker.");
newWorker = null;
} else {
try {
userDb.connect();
loggedUser = c.getValue().split(":");
if(!loggedUser[0].equals("00000000A") || !loggedUser[1].equals(userDb.selectPassword("00000000A"))){
LOGGER.warning("You need privileges to add a worker.");
} else if(newWorker.getNombre() == null || newWorker.getApellido1() == null || newWorker.getApellido2() == null){
workDb.save(newWorker); //Here's where the exception is being thrown.
} else {
workDb.save(newWorker); //Here's where the exception is being thrown.
}
} catch (ClassNotFoundException e) {
userDb.rollback();
newWorker = null;
LOGGER.warning("Exception with driver encountered.");
throw new ExpectedException(1, e.getMessage());
} catch (SQLException e) {
userDb.rollback();
newWorker = null;
throw new ExpectedException(2, e.getMessage());
} finally {
userDb.commit();
userDb.disconnect();
}
}
return newWorker;
}
}
我已经阅读了很多帖子,但我找不到它的工作方式。有没有我错过写的注释?
提前谢谢:3
编辑。应用答案后,我的主要课程:
@SpringBootApplication
@EnableSwagger2
@ComponentScan(basePackages = "com.setoncios.api")
@EnableJpaRepositories("com.setoncios.api.dao.workers")
public class GenericApiApplication {
public static void main(String[] args) {
SpringApplication.run(GenericApiApplication.class, args);
}
@Bean
public Docket swaggerSettings() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build()
.pathMapping("/");
}
}
其余方法:
@RequestMapping(value = "/worker", method = RequestMethod.POST)
public ResponseEntity<?> addWorkerInDatabase(HttpServletRequest request,
@RequestParam(value = "json", defaultValue =
"{\"dni\":\"00000000A\",\"nombre\":\"Paco\",\"apellido1\":\"Ruiz\",\"apellido2\":\"Díaz\"}") final String json){
return addDB.createResponse(request, json);
}
AddWorkerInDatabaseAction类:
@Service
public class AddWorkerInDatabaseAction extends ProcessAction{
@Autowired
private UserDatabase userDb = new UserDatabase();
@Autowired
private WorkerDAO workDb;
public AddWorkerInDatabaseAction() {
}
@Override
protected Object action(Object...args) throws ExpectedException {
Persona newWorker = new Gson().fromJson((String) args[1], Persona.class);
workDb.save(newWorker);
return newWorker;
}
}
希望它有所帮助。
答案 0 :(得分:1)
我想可能是你的注释
@EnableJpaRepositories("com.setoncios.api.dao.workers.WorkerDAO.java")
错了。此批注的默认值是用于扫描带注释的类的基础包。所以在你的情况下它应该是"com.setoncios.api.dao.workers"
。
您还可以设置basePackageClasses
以获得更多类型安全性,然后您可以将其指向WorkerDAO.class
另外,正如另一个答案所示,您应该使AddWorkerInDatabaseAction
服务并在您的控制器中自动装配。那样春天会注入必要的豆子。
答案 1 :(得分:1)
您可以将AddWorkerInDatabaseAction
类设为Spring Service。而不是将参数传递给构造函数,您可以直接将它们传递给实际的方法。
@Service
public class AddWorkerInDatabaseAction extends ProcessAction{
.....
protected Object action(HttpServletRequest request, String json) throws ExpectedException {
.....
}
在你的控制器中,你可以自动装配spring创建的这个类的bean,
private class MyController{
@Autowire
ProcessAction object;
@RequestMapping(value = "/worker", method = RequestMethod.POST)
public ResponseEntity<?> addWorkerInDatabase(HttpServletRequest request,
@RequestParam(value = "json", defaultValue =
"{\"dni\":\"00000000A\",\"nombre\":\"Paco\",\"apellido1\":\"Ruiz\",\"apellido2\":\"Díaz\"}") final String json){
return object.createResponse(request, json);
}