Question

我想以图块的形式将图片和视频上传到网络服务器但是在上传一个块后我必须再次调用outputstream来传输下一个chunk。有什么方法我只需要一次调用outstream。如果不是那么为什么每次上传一个块后调用outputstream是必要的。 我的代码当前代码是

 header('Content-type:bitmap;charset=utf-8');
 $super_parent_dir=$_POST["spd"];//super parent dic
 $parent_dir=$_POST["pd"];//parent dic
 $child_dir=$_POST["cd"];//super_child dic
 $host_no=$_POST["queue_num"];//child_dic
 $image_name=$_POST["image_name"];//file

$spd_path=$super_parent_dir;
$pd_path=$spd_path."/".$parent_dir;
$ch_path=$pd_path."/".$child_dir;
$f_folder=$ch_path."/".$host_no;

if(!is_dir($f_folder))
mkdir($f_folder, 0777);//echo $f_folder;

if(isset($_POST["Image_data"])){

$econded_string=$_POST["Image_data"];   
$decode_string=base64_decode($econded_string);
$path=$f_folder.'/'.$image_name;
$file=fopen($path,'a');
$is_written=fwrite($file,$decode_string);
fclose($file);

if($is_written>0){
    $connection=mysqli_connect("localhost","root","","imgae_db");
    $query="insert into photos values('','$path','$image_name')";
    $result=    mysqli_query($connection,$query);

}}

公共类Media_uploader扩展了AsyncTask {

private String image_file;
public Media_uploader(File image){
    this.image_file= String.valueOf(image);
}

@Override
protected void onPreExecute() {
    super.onPreExecute();
}

@Override
protected Void doInBackground(Void... params) {
    Bitmap bitmap= BitmapFactory.decodeFile(image_file);
    ByteArrayOutputStream stream=new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.JPEG,100,stream);

    byte[] array=stream.toByteArray();
    String a= Base64.encodeToString(array,Base64.DEFAULT);


    try {
        URL url=new URL("http://192.168.1.1**/db_mager/Medaia_Downloader.php");
        HttpURLConnection httpURLConnection=(HttpURLConnection)url.openConnection();

        httpURLConnection.setDoOutput(true);
        OutputStream stream1=httpURLConnection.getOutputStream();
        BufferedWriter bufferedWriter=new BufferedWriter(new OutputStreamWriter(stream1,"UTF-8"));

        String data= URLEncoder.encode("spd","UTF-8")+"="+URLEncoder.encode(Session_Data.getMyDatabase(),"UTF-8")+"&"+
                     URLEncoder.encode("pd","UTF-8")+"="+URLEncoder.encode(Session_Data.getMyCity(),"UTF-8")+"&"+
                     URLEncoder.encode("cd","UTF-8")+"="+URLEncoder.encode(Session_Data.getMyID(),"UTF-8")+"&"+
                     URLEncoder.encode("queue_num","UTF-8")+"="+URLEncoder.encode(String.valueOf(Session_Data.getActivity_Record()),"UTF-8")+"&"+
                     URLEncoder.encode("image_name","UTF-8")+"="+URLEncoder.encode(image_file,"UTF-8")+"&"+
                     URLEncoder.encode("Image_data","UTF-8")+"="+URLEncoder.encode(a,"UTF-8");

        bufferedWriter.write(data);
        bufferedWriter.flush();
        bufferedWriter.close();
        stream1.close();

        InputStream inputStream=httpURLConnection.getInputStream();
        inputStream.close();

    } catch (java.io.IOException e) {
        e.printStackTrace();
    }

    return null;
}

Answer 1

此代码是使用从Android到服务器的分段上传的示例 - 有不同的库也会支持这一点，因此值得您做一些研究以确定哪种方法最适合您，但以下内容经过测试和的工作原理。

public class VideoUploadTask extends AsyncTask<String, String, Integer> {
    /* This Class is an AsynchTask to upload a video to a server on a background thread
     * 
     */

    private VideoUploadTaskListener thisTaskListener;
    private String serverURL;
    private String videoPath;

    public VideoUploadTask(VideoUploadTaskListener ourListener) {
        //Constructor
        Log.d("VideoUploadTask","constructor");

        //Set the listener
        thisTaskListener = ourListener;
    }

    @Override
    protected Integer doInBackground(String... params) {
        //Upload the video in the background
        Log.d("VideoUploadTask","doInBackground");

        //Get the Server URL and the local video path from the parameters
        if (params.length == 2) {
            serverURL = params[0];
            videoPath = params[1];
        } else {
            //One or all of the params are not present - log an error and return
            Log.d("VideoUploadTask doInBackground","One or all of the params are not present");
            return -1;
        }


        //Create a new Multipart HTTP request to upload the video
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(serverURL);

        //Create a Multipart entity and add the parts to it
        try {
            Log.d("VideoUploadTask doInBackground","Building the request for file: " + videoPath);
            FileBody filebodyVideo = new FileBody(new File(videoPath));
            StringBody title = new StringBody("Filename:" + videoPath);
            StringBody description = new StringBody("test Video");
            MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
            reqEntity.addPart("videoFile", filebodyVideo);
            reqEntity.addPart("title", title);
            reqEntity.addPart("description", description);
            httppost.setEntity(reqEntity);
        } catch (UnsupportedEncodingException e1) {
            //Log the error
            Log.d("VideoUploadTask doInBackground","UnsupportedEncodingException error when setting StringBody for title or description");
            e1.printStackTrace();
            return -1;
        }

        //Send the request to the server
        HttpResponse serverResponse = null;
        try {
            Log.d("VideoUploadTask doInBackground","Sending the Request");
            serverResponse = httpclient.execute( httppost );
        } catch (ClientProtocolException e) {
            //Log the error
            Log.d("VideoUploadTask doInBackground","ClientProtocolException");
            e.printStackTrace();
        } catch (IOException e) {
            //Log the error
            Log.d("VideoUploadTask doInBackground","IOException");
            e.printStackTrace();
        }

        //Check the response code
        Log.d("VideoUploadTask doInBackground","Checking the response code");
        if (serverResponse != null) {
            Log.d("VideoUploadTask doInBackground","ServerRespone" + serverResponse.getStatusLine());
            HttpEntity responseEntity = serverResponse.getEntity( );
            if (responseEntity != null) {
                //log the response code and consume the content
                Log.d("VideoUploadTask doInBackground","responseEntity is not null");
                try {
                    responseEntity.consumeContent( );
                } catch (IOException e) {
                    //Log the (further...) error...
                    Log.d("VideoUploadTask doInBackground","IOexception consuming content");
                    e.printStackTrace();
                }
            } 
        } else {
            //Log that response code was null
            Log.d("VideoUploadTask doInBackground","serverResponse = null");
            return -1;
        }

        //Shut down the connection manager
        httpclient.getConnectionManager( ).shutdown( ); 
        return 1;
    }

    @Override
    protected void onPostExecute(Integer result) {
        //Check the return code and update the listener
        Log.d("VideoUploadTask onPostExecute","updating listener after execution");
        thisTaskListener.onUploadFinished(result);
    }

}

如何将大文件从android上传到webserver

1 个答案: