我正在使用Delphi 10.1 Berlin
我想使用TBytes
将图像数据作为TRestRequest
发送到Rest服务,但我找不到将TBytes
传递给TRestRequest.AddBody()
方法的方法,或任何其他方法。
POST http://myserver:1111//Openxxx/RecxxxLxxxPxxxx HTTP/1.1 Content-Type: text/json Host: myserver:1111 Content-Length: 28892 Expect: 100-continue Connection: Keep-Alive [255,216,255,224,0,16,74,70,73,70,0,1,1,0,0,1,0,1,0,0,255,219,0,132,0,9, ... ... ... 130,130,252,168,127,164,63,164,41,109,204,245,62,106,51,135,12,146,63,255,217]
答案 0 :(得分:4)
TRESTRequest.AddBody()
有一个重载,接受typecast
作为输入。您可以使用TBytesStream
类将TStream
打包到TBytes
。
TStream
或者,请使用TRESTRequestParameterList.AddItem
代替procedure TForm1.Button1Click(Sender: TObject);
var
ABytes: TBytes;
AStream: TBytesStream;
begin
ABytes := ...;
try
AStream := TBytesStream.Create(ABytes);
RESTRequest1.AddBody(AStream, ctIMAGE_JPEG);
RESTRequest1.Execute;
finally
AStream.Free;
end;
end;
:
TBytes
话虽这么说,我发现procedure TForm1.Button1Click(Sender: TObject);
var
ABytes: TBytes;
begin
ABytes := ...
RESTRequest1.Params.AddItem('body', ABytes, pkGETorPOST, [poDoNotEncode], ctIMAGE_JPEG);
RESTRequest1.Execute;
end;
过于复杂和错误/限制。更多的时候,Indy的TRESTClient
更容易使用,例如:
TIdHTTP
procedure TForm1.Button1Click(Sender: TObject);
var
ABytes: TBytes;
AStream: TBytesStream;
begin
ABytes := ...;
try
AStream := TBytesStream.Create(ABytes);
IdHTTP1.Request.ContentType := 'image/jpeg';
IdHTTP1.Post('http://myserver:1111//Openxxx/RecxxxLxxxPxxxx', AStream);
finally
AStream.Free;
end;
end;
答案 1 :(得分:0)
我已经解决了我的问题,如下所示:
function BytesToStr(abytes: tbytes): string;
var
abyte: byte;
begin
for abyte in abytes do
begin
Result := result + IntToStr(abyte) + ',';
end;
Result := '[' + Copy(Result, 1, Length(Result) - 1) + ']';
end;
procedure TForm1.Button1Click(Sender: TObject);
var
ABytes: TBytes;
begin
ABytes := TFile.ReadAllBytes('images.jpg');
RESTRequest1.Params.AddItem('body', BytesToStr(ABytes), pkREQUESTBODY, [], ctAPPLICATION_JSON);
RESTRequest1.Execute;
end;