我有5张桌子
psa_aso_target psa_aso_branch psa_aso_targetdetails psa_aso_dept
-------------- --------------- --------------------- ------------
target_id[PK] branch_id[PK] target_id[FK] dept_id[PK]
branch_id[FK] branch_desc[FK] dept_id[FK] dept_desc
grade_id[FK]
psa_aso_grade
-------------
grade_id
grade_code
这是我表的示例数据
psa_aso_branch psa_aso_dept psa_aso_grade psa_aso_target
b1 | Jakarta d1 | Dept1 g1 | 101 t1 | b2
b2 | Surabaya d2 | Dept2 g2 | 201 t2 | b3
b3 | Semarang d3 | Dept3 g3 | 301
g4 | 401
g5 | 501
psa_aso_targetdetails
t1 | d1 | g1 t1 | d2 | g1 t2 | d3 | g3
t1 | d1 | g2 t1 | d2 | g2 t2 | d3 | g4
t1 | d1 | g3 t1 | d2 | g3
t1 | d1 | g4 t2 | d1 | g1
t1 | d1 | g5 t2 | d1 | g4
我需要什么查询来获得此预期结果
branch_id | branch_desc | dept_id | dept_desc | string_agg (grade_code)
-----------------------------------------------
b1 | Jakarta | d1 | dept1 | g1,g2,g3,g4,g5
b1 | Jakarta | d1 | dept2 | g1,g2,g3,g4,g5
b1 | Jakarta | d1 | dept3 | g1,g2,g3,g4,g5
b2 | Surabaya | d2 | dept2 | g4,g5
b2 | Surabaya | d2 | dept3 | g1,g2,g3,g4,g5
b3 | Semarang | d2 | dept3 | g2,g3,g5
b3 | Semarang | d2 | dept3 | g1,g2,g3,g4,g5
b3 | Semarang | d2 | dept3 | g1,g2,g5
解释是：我想选择所有尚未在psa_aso_targetdetails上选择的分数和部门（在该分支和部门上），以便输出高于
答案 0 :(得分：0)
尝试：
select t1.branch_id,t1.branch_desc,t4.dept_id, t4.dept_desc, string_agg (grade_code)
from psa_aso_branch t1
join psa_aso_target t2 on t1.branch_id = t2.branch_id
join psa_aso_targetdetails t3 on on t3.target_id = t1.target_id
join psa_aso_dept t4 on t4.dept_id = t3.dept_id
join psa_aso_grade t5 on t5.grade_id = t3.grade_id
group by t1.branch_id,t1.branch_desc,t4.dept_id, t4.dept_desc