Question

我有一个包含100000条记录的表格，我得到97000条记录，作为以下查询的一部分，如何获取剩余的30000条记录。我试过不等于'H.RESOURCE_ID <> SQ.CPNT_OG_ID'但没有得到正确的数据？

SELECT H.pernr AS "STUD_ID",
       SQ.CPNT_TYP_ID,
       SQ.CPNT_ID,
       TO_CHAR (SQ.REV_DTE, 'MON-DD-YYYY HH24:MI:SS') AS REV_DTE,
       CASE                                                           --WAIVED
          WHEN sq.CPNT_TYP_ID = 'VIDEO' AND enrollment_status = 'Complete'
          THEN
             'VIDEO-COMPLETE'
          WHEN sq.CPNT_TYP_ID = 'VIDEO' AND enrollment_status <> 'Complete'
          THEN
             'VIDEO-WAIVED'
          WHEN     sq.CPNT_TYP_ID = 'CERTIFICATION'
               AND enrollment_status = 'Complete'
          THEN
             'CERT-COMPLETE'
          WHEN     sq.CPNT_TYP_ID = 'CERTIFICATION'
               AND enrollment_status <> 'Complete'
          THEN
             'CERT-WAIVED'
          WHEN sq.CPNT_TYP_ID = 'CDOC' AND enrollment_status = 'Complete'
          THEN
             'CDOC-COMPLETE'
          WHEN sq.CPNT_TYP_ID = 'CDOC' AND enrollment_status <> 'Complete'
          THEN
             'CDOC-WAIVED'
          WHEN     sq.CPNT_TYP_ID = 'ELEARNING'
               AND enrollment_status = 'Complete'
          THEN
             'Elearning-COMPLETE-PASSED'
          WHEN     sq.CPNT_TYP_ID = 'ELEARNING'
               AND enrollment_status <> 'Complete'
          THEN
             'Elearning-WAIVED'
          ELSE
             NULL
       END
          "CMPL_STAT_ID",
       TO_CHAR (H.COMPLETION_DATE, 'MON-DD-YYYY HH24:MI:SS')
          AS COMPLETION_DATE,
       'RECORD_Admin'
          AS "ESIG_MEANING_CODE_ID",
       NULL                                           AS "LST_UPD_USR",
       sq.rev_num                                     AS "REV_NUM",
       'LEARNSHARE'                                   AS "COMMENTS"
  FROM ZB_USR_HISTORY_NEW H
       JOIN
       (SELECT DISTINCT CPNT_ID,
                        CPNT_TYP_ID,
                        CPNT_OG_ID,
                        REV_DTE,
                        REV_NUM,
                        CPNT_COURSE_NUM
          FROM TBL_ZIM_ITEM_new
         WHERE VALID = '1' AND app_id LIKE '%en-us%' OR LENGTH (app_id) < 9)
       SQ
          ON (H.RESOURCE_ID = SQ.CPNT_OG_ID);

Answer 1

只需用LEFT JOIN替换JOIN即可。您可以在SQL中使用LEFT JOIN或RIGHT JOIN，以便获取不满足连接条件的记录。在不存在的行中选择的列将为NULL。

在ORACLE中加入表

1 个答案: