Question

在一个简单的刽子手游戏上工作，我试图用keyup()抓住用户输入，但是当我将它记录到控制台时我意识到某些事情并非如此工作正常......这是我的代码：

$(document).keyup(function(e) {

    userInput = e.value;
    console.log(userInput);

});

我也试过这样做，但它也没有用。

$(document).keyup(function(e) {

    userInput = $(this).val();
    console.log(userInput);

});

哦，顺便说一下， userInput是一个全局变量。

Answer 1

您必须从活动的#encrypt user_input = input ("Enter string: ") for char in user_input: #for every character in input cipher_num = (ord(char))+3%26 #using ordinal to find the number cipher= '' cipher = chr(cipher_num) # using chr to convert back to a letter cipher_text = '' #add all values to string cipher_text = (cipher_text+cipher) print (cipher_text) #decrypt for char in cipher_text: #for every character in the encrpted text decrypt_num = (ord(char))-3%26 decrypt= '' decrypt = chr(decrypt_num) decrypt_text = '' decrypt_text = (decrypt_text+decrypt) print(decrypt_text)属性中获取value。请尝试以下方式：

＆＃13;

target

＆＃13;

$('#txtInput').on('keyup', function(e) {

    var userInput = e.target.value;
    console.log(userInput);

});

＆＃13;

Answer 2

$( "#whichkey" ).on( "keydown", function( event ) {
  $( "#log" ).html( event.type + ": " +  event.which );
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="whichkey" placeholder="type something">
<div id="log"></div>

使用event.which

描述：对于键或鼠标事件，此属性指示已按下的特定键或按钮。

如何使用jQuery .keyup（）函数捕获键盘输入

2 个答案: