我一直在寻找this tutorial和this example试图通过JSON(< 9.5)/ JSONB(* 9.5)数据查找子字符串的高效方法。
例如,我有这些数据:
CREATE TABLE public.foo
(
row_id SERIAL PRIMARY KEY,
data json
);
INSERT INTO foo VALUES (1,
'{ "name": "Book the First", "author": "Bob", "text_entry": "White Cow Walked Over the Moon" } ');
INSERT INTO foo VALUES (2,
'{ "name": "Book the Second", "author": "Charles", "text_entry": "Humptey Dumptey sat on the Moon" } ');
INSERT INTO foo VALUES (3,
'{ "name": "Book the Third", "author": "Jim", "text_entry": "Red Fox jumped over Brown Dog" } ');
我正在寻找一种只搜索的方法" text_entry"并返回任何具有子串"月亮" (在这种情况下,它将是id = 1& 2)。预期回报:
text_entry
"White Cow Walked Over the Moon" ## has the substring "the Moon"
"Humptey Dumptey sat on the Moon" ## has the substring "the Moon"
到目前为止,我的查询看起来像这样:
SELECT data->'text_entry'->'%the Moon%' AS query FROM foo;
ERROR: cannot extract element from a scalar
********** Error **********
有没有优雅的方法来查询JSON / B中的子串?
答案 0 :(得分:0)
我正在寻找一种方法来搜索“text_entry”并返回任何具有子串“月亮”的案例
SELECT data->>'text_entry' as query
FROM foo
WHERE data->>'text_entry' LIKE '%the Moon%';
- >
query
---------------------------------
White Cow Walked Over the Moon
Humptey Dumptey sat on the Moon
(2 rows)