Question

我得到一个随机单词列表，我需要与描述或其他文本字段中的任何单词匹配，这些单词不必是连续的。这应该给我任何比赛。如果您考虑它，就像任何单词匹配搜索功能一样。

我回来的字符串，我分成一个空白区域，这会产生一个包含每行不同单词的表格。

如何重用该表来查找任何单词的匹配项，因为我不能使用WHERE IN子句。

DECLARE @split TABLE(word NVARCHAR(2000))

SELECT *
          FROM StockSummary
         WHERE Reference in (select word from @split)
            OR Name in (select word from @split)
            OR AlternativeReference in (select word from @split)
            OR InternalReference in (select word from @split)

Answer 1

效率不是很高，但我认为这就是你要找的东西。使用全文索引编写更好的方法。

DECLARE @split TABLE(word NVARCHAR(2000));

SELECT DISTINCT ss.*
FROM StockSummary ss
INNER JOIN @split s
    ON ss.Reference LIKE '%' + s.word + '%'
    OR ss.Name LIKE '%' + s.word + '%'
    OR ss.AlternativeReference LIKE '%' + s.word + '%'
    OR ss.InternalReference LIKE '%' + s.word + '%';

请注意，这基本上是执行中的交叉连接。

查找包含所有字词的行：

DECLARE @split TABLE(word NVARCHAR(2000));

SELECT Reference, Name, AlternativeReference, InternalReference
FROM (
    SELECT DISTINCT ss.Reference, ss.Name, ss.AlternativeReference, ss.InternalReference, s.word
    FROM StockSummary ss
    INNER JOIN @split s
        ON ss.Reference LIKE '%' + s.word + '%'
        OR ss.Name LIKE '%' + s.word + '%'
        OR ss.AlternativeReference LIKE '%' + s.word + '%'
        OR ss.InternalReference LIKE '%' + s.word + '%';
)
GROUP BY Reference, Name, AlternativeReference, InternalReference
HAVING COUNT(*) = (SELECT COUNT(*) FROM @split);

如果你的列表中有相同的单词两次，DISTINCT将处理重复项，结果中不需要两次（你需要用CHARINDEX做更多的事情）。

Answer 2

DECLARE @Test TABLE (TestId INT IDENTITY, Test VARCHAR(8), Test2 VARCHAR(8), Test3 VARCHAR(8));

INSERT INTO @Test (Test, Test2, Test3) VALUES ('Duck', NULL, NUll), (NULL, NULL, 'Duck'), ('Sit', NULL, NULL), ('Kneel', NULL, NULL), (NULL, 'Hey', NULL);

--Data as is
Select *
From @Test

--Insert in some hunting data into a table
DECLARE @Find TABLE (word VARCHAR(8));
INSERT INTO @Find (word) VALUES ('Duck'),('Sit');

--match cte on multiple join conditions
; With x as 
    (
    SELECT
        a.*
    ,   CASE WHEN b.Word IS NOT NULL OR c.word IS NOT NULL OR d.word IS NOT NULL THEN 1 ELSE 0 END AS Found
    From @Test a
        LEFT JOIN @Find b ON a.Test = b.Word
        LEFT JOIN @Find c ON a.Test2 = c.Word
        LEFT JOIN @Find d ON a.Test3 = d.Word
        )
Select *
From x
WHERE Found = 1

“LIKE”和“IN”选择条件SQL

2 个答案: