Question

我一直在编写一个在服务器上运行远程脚本的程序。所以，我需要用条形图显示进度但不知何故，当我运行我的代码时，GUI开始冻结。我使用过QThread和SIGNAL，但遗憾的是无法成功。

以下是我的代码;

class dumpThread(QThread):

    def __init__(self):
        QThread.__init__(self)

    def __del__(self):
        self.wait()

    def sendEstablismentCommands(self, connection):

        # Commands are sending sequently with proper delay-timers #

        connection.sendShell("telnet localhost 21000")
        time.sleep(0.5)
        connection.sendShell("admin")
        time.sleep(0.5)
        connection.sendShell("admin")
        time.sleep(0.5)
        connection.sendShell("cd imdb")
        time.sleep(0.5)
        connection.sendShell("dump subscriber")

        command = input('$ ')

    def run(self):
        # your logic here              
        # self.emit(QtCore.SIGNAL('THREAD_VALUE'), maxVal)
        self.sendEstablismentCommands(connection)    

class progressThread(QThread):

    def __init__(self):
        QThread.__init__(self)

    def __del__(self):
        self.wait()


    def run(self):
        # your logic here
        while 1:      
            maxVal = 100
            self.emit(SIGNAL('PROGRESS'), maxVal)

class Main(QtGui.QMainWindow):
    def __init__(self):
        QtGui.QMainWindow.__init__(self)
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)
        self.ui.connectButton.clicked.connect(self.connectToSESM)



    def connectToSESM(self):
        ## Function called when pressing connect button, input are being taken from edit boxes. ##
        ## dumpThread() method has been designed for working thread seperate from GUI. ##

        # Connection data are taken from "Edit Boxes"
        # username has been set as hardcoded

        ### Values Should Be Defined As Global ###
        username = "ntappadm"
        password = self.ui.passwordEdit.text()
        ipAddress = self.ui.ipEdit.text()

        # Connection has been established through paramiko shell library
        global connection

        connection = pr.ssh(ipAddress, username, password)
        connection.openShell()
        pyqtRemoveInputHook()  # For remove unnecessary items from console

        global get_thread

        get_thread = dumpThread() # Run thread - Dump Subscriber
        self.progress_thread = progressThread()

        self.progress_thread.start()
        self.connect(self.progress_thread, SIGNAL('PROGRESS'), self.updateProgressBar)

        get_thread.start()     




    def updateProgressBar(self, maxVal):

        for i in range(maxVal):
            self.ui.progressBar.setValue(self.ui.progressBar.value() + 1)
            time.sleep(1)
            maxVal = maxVal - 1

            if maxVal == 0:
                self.ui.progressBar.setValue(100)

    def parseSubscriberList(self):
        parsing = reParser()

    def done(self):
        QtGui.QMessageBox.information(self, "Done!", "Done fetching posts!")




if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    main = Main()
    main.show()
    sys.exit(app.exec_())

我期待看到updateProgressBar方法已经使用SIGNAL调用，因此进程通过单独的线程。我找不到我失踪的地方。

感谢您的帮助

Answer 1

实际上有两个问题。我注意到的一件事是，如果Python线程不用于从串行端口读取等IO操作，那么Python线程就会贪婪。如果您告诉线程运行计算或者与IO无关的事情，则线程将占用所有处理，并且不希望让主线程/事件循环运行。第二个问题是信号很慢......非常慢。我注意到如果你从一个线程发出一个信号并且速度非常快，它会大大减慢程序的速度。

所以问题的核心是，线程占用了所有的时间并且你发出的信号非常快，这将导致减速。

为了清晰和易用，我会使用新式信号和插槽。 docs

class progressThread(QThread):

    progress_update = QtCore.Signal(int) # or pyqtSignal(int)

    def __init__(self):
        QThread.__init__(self)

    def __del__(self):
        self.wait()


    def run(self):
        # your logic here
        while 1:      
            maxVal = 100
            self.progress_update.emit(maxVal) # self.emit(SIGNAL('PROGRESS'), maxVal)
            # Tell the thread to sleep for 1 second and let other things run
            time.sleep(1)

连接新样式信号

...
self.progress_thread.start()
self.process_thread.progress_update.connect(self.updateProgressBar) # self.connect(self.progress_thread, SIGNAL('PROGRESS'), self.updateProgressBar)
...

修改对不起还有另外一个问题。当信号调用函数时，您无法永远保持该函数。该函数没有在主事件循环上运行的单独线程中运行，主事件循环等待运行直到退出该函数。

更新进度睡眠1秒并保持循环。悬挂来自于保持这个功能。

def updateProgressBar(self, maxVal): for i in range(maxVal): self.ui.progressBar.setValue(self.ui.progressBar.value() + 1) time.sleep(1) maxVal = maxVal - 1 if maxVal == 0: self.ui.progressBar.setValue(100)

最好像
那样编写进度条
class progressThread(QThread): progress_update = QtCore.Signal(int) # or pyqtSignal(int) def __init__(self): QThread.__init__(self) def __del__(self): self.wait() def run(self): # your logic here while 1: maxVal = 1 # NOTE THIS CHANGED to 1 since updateProgressBar was updating the value by 1 every time self.progress_update.emit(maxVal) # self.emit(SIGNAL('PROGRESS'), maxVal) # Tell the thread to sleep for 1 second and let other things run time.sleep(1) def updateProgressBar(self, maxVal): self.ui.progressBar.setValue(self.ui.progressBar.value() + maxVal) if maxVal == 0: self.ui.progressBar.setValue(100)

带线程的PyQt进度条更新

1 个答案: