Question

我有两张表 App 和商店

分组：分组的应用程序计数，即HasGroup = 1
NonGrouped：未分组的应用程序计数，即HasGroup = 0
分组（％）：分组的应用程序的百分比，即HasGroup = 1
NonGrouped（％）：未分组的应用程序百分比，即HasGroup = 0
AverageNonGrouped（％）：它是分组应用程序的平均值，即(Invidual NonGrouped(%) / total NonGrouped(%))*100。 ABC的例子是(75/ 165)*100 = 45.45，类似于XYZ，它是(50/ 165)*100 = 30.30。此处165是75+50+40

我的查询如下：

SELECT 
AppName, 
SUM( CASE HasGroup  WHEN 1 THEN 1 ELSE 0 END ) AS Grouped,
SUM( CASE HasGroup WHEN 0 THEN 1 ELSE 0 END ) AS NonGrouped,
ROUND(((SUM( CASE HasGroup  WHEN 1 THEN 1 ELSE 0 END ) / 
    (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
        SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) AS GroupedPercentage,
ROUND(((SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) / 
    (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
        SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) AS NonGroupedPercentage
FROM
    Apps
    INNER JOIN Store
        ON (Apps.Store = Store.Store) 
        AND AppName !='' GROUP BY AppName

我能够找到除AverageNonGrouped（％）以外的列，因为我不知道如何获得总NonGrouped（％），有谁可以帮我这个

Answer 1

这是一个很大的查询，但它完成了工作（我已经在一个数据集上进行了测试）

SELECT 
    AppName, 
    SUM( CASE HasGroup  WHEN 1 THEN 1 ELSE 0 END ) AS Grouped,
    SUM( CASE HasGroup WHEN 0 THEN 1 ELSE 0 END ) AS NonGrouped,
    ROUND(((SUM( CASE HasGroup  WHEN 1 THEN 1 ELSE 0 END ) / 
    (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
        SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) AS GroupedPercentage,
    ROUND(((SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) / 
    (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
        SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) AS NonGroupedPercentage,

    ROUND(((SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) / 
    (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
        SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) / 

    (SELECT SUM(NonGroupedPercentage)
    FROM (
    SELECT 
        ROUND(((SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) / 
            (SUM( CASE HasGroup  WHEN 0 THEN 1 ELSE 0 END ) + 
                SUM( CASE HasGroup WHEN 1 THEN 1 ELSE 0 END )))*100), 2) AS NonGroupedPercentage
    FROM
        apps
    INNER JOIN store
            ON (apps.Store = store.Store) 
            AND AppName !='' 
    GROUP BY AppName 
    ) AS total) *100  AS AverageNonGroupedPercentage
FROM
    apps
INNER JOIN store
    ON (apps.Store = store.Store) 
    AND AppName !='' 
GROUP BY AppName

使用MySQL计算行和查找平均值的总和

1 个答案: