Question

如果在Mule中编写的查询中SQL Server查询中已有值，那么如何将空值更新为列？有效负载包含Data weave的结果集。在更新时，我想检查更新值是否为null，如果它“not null”，则只应更新值。

查询是：

UPDATE dbo.ix_str_store 
SET NAME = '#[payload.Site.Name]', 
    ADDRESS1 = '#[payload.Site.Address1]',
    ADDRESS2 = '#[payload.Site.Address2]',
    ADDRESSCITY = '#[payload.Site.AddressCity]',
    ADDRESSSTATE = '#[payload.Site.AddressState]',
    ADDRESSPOSTALCODE = '#[payload.Site.AddressPostalCode]', 
    ADDRESSCOUNTRY = '#[payload.Site.AddressCountry]', 
    EMAIL = '#[payload.Site.Email]', 
    PHONE = '#[payload.Site.Phone]', 
    FAX = '#[payload.Site.Fax]', 
    REGION = '#[payload.Site.Region]', 
    COMPANY = '#[payload.Site.Company]', 
    DESC1 = '#[payload.Site.Desc1]', 
    DESC2 = '#[payload.Site.Desc2]',
    DESC7 = '#[payload.Site.Desc7]',
    DESC8 = '#[payload.Site.Desc8]',
    VALUE1 = #[payload.Site.Value1], 
    VALUE2 = #[payload.Site.Value2], 
    DBTIME = CURRENT_TIMESTAMP, 
    DBSTATUS = 1 
WHERE 
    STORENUMBER = #[payload.Site.StoreNumber]

Answer 1

试试吧

isnull(new_value,old_value)

Answer 2

在这种情况下，而不是使用insert into (...) values(...)构造;使用insert into .. select from构造如

insert into table (..)
select ..,
case when new_col_val is not null then new_col_val else old_col_val end
from ...

（或）您也可以使用COALESCE()函数代替CASE表达coalesce(new_col_val, old_col_val)

如果在SQL Server查询中已有值时，如何将空值更新为列

2 个答案: