有人可以帮助我makeMove方法

Question

我正在尝试创建一个tic tac toe游戏类，其中一个问题是makeMove方法，我必须使用switch方法。当我使用测试器类时，它不起作用。有人能告诉我答案/问题应该是什么。 这是tic tac toe class

public class TicTacToe
{
private String[][] board;
private int turn;
private boolean hasWinner;
private boolean bale;
/**
 * Constructs an empty game board.  Sets the turn to zero.
 */
public TicTacToe()
{
    board = new String[][] {
        {"1", " | ", "2", " | ", "3"},
        {"-", "-|-", "-", "-|-", "-"},
        {"4", " | ", "5", " | ", "6"},
        {"-", "-|-", "-", "-|-", "-"},
        {"7", " | ", "8", " | ", "9"},
    };
    turn = 0;
}

/**
 * Prints the two dimensional array gameboard to the console with an empty line before and after
 */
public void drawBoard()
{


            for(int rows = 0; rows < board.length; rows++)
            {
                for( int cols = 0; cols < board[0].length; cols++)
                {
                    System.out.print(board[rows][cols] );
                }
                System.out.println();


            }


     }

   /**
 * Precondition: the location will be a number 1 through 9
 * Hint: Loop through the array and see if the number still exists there.
 * @param location the numeric location according to the initial configuration
 * @return true if the space is unoccupied and legal, false otherwise
 */
public boolean validMove(int location)
{
       for (int row = 0; row < board.length; row++) {
        for (int col = 0; col < board[0].length; col++) {

               if( board[row][col].equals( location))
               {
                   bale = false;

                }
                else
                {
                    bale = true;
                }

         }

     }
           return bale;     
   }








/**
 * Preconditions: the location is valid, the symbol is a single character: X or O.
 * @param location the numeric location according to the initial configuration
 * @param symbol the player's symbol
 */
public void makeMove(int location, String symbol)
{
    int row = 0;
    int col = 0;
    //map the numeric location to the row and column on the game board
    switch(location)
    {
        case 1: row = 0; col = 0; break;
        case 2: row = 0; col = 2; break;
        /*#
         * Insert the rest of the cases below.  More info on switch statements here:
         * http://docs.oracle.com/javase/tutorial/java/nutsandbolts/switch.html
         * One use is to replace a long series of if/else if/else statements.
         */
         case 3: row = 0; col = 1; break;
          case 4: row = 2; col = 0; break;
           case 5: row = 2; col = 2; break;
            case 6: row = 2; col = 1; break;
             case 7: row = 1; col = 0; break;
              case 8: row = 1; col = 2; break;
               case 9: row = 1; col = 1; break;
    }
    /*#
     * Insert the symbol in the appropriate location below
     */
    location = symbol;


}
/**
 * Checks if the winning condition has been met for either player.
 * @return true if there is a winner, false otherwise
 */
public boolean hasWinner()
{
    /*#
     * if there is a winner from hasWinner("X") or hasWinner("O"), return true
     * otherwise false
     */
    hasWinner = false; 

   for (int i = 0; i < board.length; i+=2) 
   {
       if ((board[i][0].equals("X") == true) && (board[i][2].equals("X") == true) && (board[i][4].equals("X") == true))
       {
            hasWinner = true;  

       } 
       else if ((board[i][0].equals("O") == true) && (board[i][2].equals("O") == true) && (board[i][4].equals("O") == true))
       {
            hasWinner = true;  

       } 
   }

   for (int i = 0; i < board.length; i+=2) 
   {
       if ((board[0][i].equals("X") == true) && (board[2][i].equals("X") == true) && (board[4][i].equals("X") == true))
       {
           hasWinner = true; 

       }  
       else if ((board[0][i].equals("O") == true) && (board[2][i].equals("O") == true) && (board[4][i].equals("O") == true))
       {
           hasWinner = true; 

       }  
   }      

   if( (board[0][0].equals("X")==true) && (board[2][2].equals("X")==true) && (board[4][4].equals("X") == true)) 
   {
       hasWinner = true;

   }
   else if( (board[0][0].equals("O")==true) && (board[2][2].equals("O")==true) && (board[4][4].equals("O") == true)) 
   {
       hasWinner = true;

   }

   if( (board[4][4].equals("X")==true) && (board[2][2].equals("X")==true) && (board[0][0].equals("X") == true)) 
   {
       hasWinner = true;

   }
   else if( (board[4][4].equals("O")==true) && (board[2][2].equals("O")==true) && (board[0][0].equals("O") == true)) 
   {
       hasWinner = true;

   }

   return hasWinner; 
}

/**
 * @param symbol the symbol of the player to check for a win condition
 * @return true if there is a winner, false otherwise
 */
private boolean hasWinner(String symbol)
{
    /*#
     * return true if there are three of symbol in a row vertically, horizontally, or diagonally
     * hint: there is a gap of one string between each actual occupiable space, so when looping,
     * you can change your updater from i++ to i+=...well, I'll leave it to you to figure out what
     * number to use after the +=. 
     */


    return true;

}

/**
 * For debugging and testing only.
 * @param state a valid board configuration
 */
public void setGameState(String[][] state)
{
    board = state;
}

}

这是测试人员类

public class TicTacToeTester
{
public static void main(String[] args)
{
    TicTacToe t = new TicTacToe();
    t.drawBoard();
    System.out.println("Expected: \n\n1 | 2 | 3\n--|---|--\n4 | 5 | 6\n--|---|--\n7 | 8 | 9\n\n");
    System.out.println(t.validMove(4));
    System.out.println("Expected: true");
    t.makeMove(4, "X");
    t.drawBoard();
    System.out.println("Expected: \n\n1 | 2 | 3\n--|---|--\nX | 5 | 6\n--|---|--\n7 | 8 | 9\n\n");
    System.out.println(t.validMove(4));
    System.out.println("Expected: false");
    t.makeMove(9, "O");
    t.drawBoard();
    System.out.println("Expected: \n\n1 | 2 | 3\n--|---|--\nX | 5 | 6\n--|---|--\n7 | 8 | O\n\n");
}
}

此外，我尝试多次和多天来做这件事，但是代码并没有按预期的那样做

Answer 1

错误来自location=symbol;，你试图将字符串转换为int。如果你想这样做，那么使用Integer.parseInt() or Integer.valueOf()，但是即使这样，也要警告你，{{1} }}

Answer 2

首先，这条线没有编译，因为你要将一个字符串赋给一个int：

location = symbol;

我认为你打算在这里这样做？

board[row][col] = symbol;

然后，switch语句中的索引关闭。例如，9应转换为第4行和第4列：

最后一点，你要写的东西......

if(board[i][0].equals("X") == true)

...你可以把它们写成......

if(board[i][0].equals("X"))

...并获得相同的行为。如果语句中的表达式的计算结果为true，则语句执行正文中的代码。你正在做一个没有做任何事情的额外步骤，因为将任何布尔值与true进行比较只会返回你所拥有的布尔值。