Question

我正在尝试将基于Rest的Web服务应用程序部署到Weblogic控制台12C上。为此，我使用了Spring-Jersey实现和Spring依赖注入在尝试访问我的服务时，我必须使用Weblogic的/ resources / *路径，因为/ rest / *不起作用。此外，SpringServlet没有被调用，但Weblogic自己的JAX-RS Jersey实现正在运行。我已经检查过，在应用程序启动期间，bean正在通过弹簧正确创建任何人都可以提供有关如何使用我的实现而不是Weblogic的默认JAX-RS解决方案的解决方案。

web.xml中。

＆＃13;

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>TestWeb</display-name>
  <context-param>
	<param-name>contextConfigLocation</param-name>
	<param-value>classpath:testWebContext.xml</param-value>
  </context-param>
  <listener>
	<listener-class>
		org.springframework.web.context.ContextLoaderListener
	</listener-class>
  </listener>
  <listener>
	<listener-class>
		org.springframework.web.context.request.RequestContextListener
	</listener-class>
  </listener>
  <servlet>
  	<servlet-name>jersey</servlet-name>
  	<servlet-class>
		com.sun.jersey.spi.spring.container.servlet.SpringServlet
	</servlet-class>
	<init-param>
		<param-name>POJOMappingFeature</param-name>
		<param-value>true</param-value>
	</init-param>
	<init-param>
      <param-name>com.sun.jersey.config.property.packages</param-name>
      <param-value>com.test.web.service</param-value>
    </init-param>
	<load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
	<servlet-name>jersey</servlet-name>
	<url-pattern>/rest/*</url-pattern>
  </servlet-mapping>
  
</web-app>

＆＃13;

testWebContext.xml

＆＃13;

<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns:context="http://www.springframework.org/schema/context"
	xsi:schemaLocation="http://www.springframework.org/schema/beans
	http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
	http://www.springframework.org/schema/context
	http://www.springframework.org/schema/context/spring-context-3.0.xsd">

	<bean id="testWebService" class="com.test.web.service.TestWebServiceImpl">
		<property name="testWebBo" ref="testWebBo"/>
	</bean>
	<bean id="testWebBo" class="com.test.web.bo.TestWebBOImpl"/>
	
	<bean name="destReader" init-method="readDestinations" class="com.test.web.util.DestinationReader"/>

</beans>

＆＃13;

Answer 1

将weblogic.xml文件插入已部署应用的WEB-INF文件夹中。

这里有一个示例文件：

 <?xml version="1.0" encoding="UTF-8"?>
 <weblogic-web-app xmlns="http://xmlns.oracle.com/weblogic/weblogic-web-app">  
 <library-ref>    
    <library-name>jax-rs</library-name>    
    <specification-version>2.0</specification-version>  
    <implementation-version>2.5.1</implementation-version>    
    <exact-match>false</exact-match>
 </library-ref>
 <container-descriptor>
    <prefer-application-packages>
        <package-name>org.glassfish.jersey.client.*</package-name>
        <package-name>org.glassfish.jersey.servlet.*</package-name> 
        <package-name>org.glassfish.jersey.jaxb.internal.*</package-name>   
        <package-name>com.sun.research.ws.wadl.*</package-name>
        <package-name>org.glassfish.hk2.*</package-name>
        <package-name>org.jvnet.hk2.*</package-name>
        <package-name>jersey.repackaged.org.objectweb.asm.*</package-name>
        <package-name>org.objectweb.asm.*</package-name>
        <package-name>com.sun.ws.rs.ext.*</package-name>
        <package-name>org.aopalliance.*</package-name>
        <package-name>javax.annotation.*</package-name>
        <package-name>javax.inject.*</package-name>
        <package-name>javax.ws.rs.*</package-name>
        <package-name>jersey.repackaged.com.google.common.*</package-name>
        <package-name>javassist.*</package-name>
        </prefer-application-packages>
    </container-descriptor>
    <context-root>your root name</context-root>
  </weblogic-web-app>

使用Springservlet实现Weblogic Rest Service

1 个答案: