Question

我错过了什么？我正在构建一个动态查询并准备postgres的查询。它应该工作但是eval语句并没有发挥它的魔力。我错过了什么？

除了eval之外，还有另一种传递带有多个变量的字符串的方法吗？感谢。

简要说明。

$condition = array();
$values    = array();
$pgarray   = array();

$country = 254;
$city    = "Seattle";

$condition[] = " AND city = $";
$values[]    = $city;
$pgarray[]   = "\$city";

$condition[] = " AND country = $";
$values[]    = $country;
$pgarray[]   = "\$country";

$as = sizeof($condition);

for ( $x=0; $x<$as; $x++ ) {
   $index = $x + 1;  //We need to start at one not 0
   $qclause = $qclause . $condition[$x] . $index . "  ";
}

// This is what qclause equates to.
// AND city = $1 AND country = $2 

$pgarray = implode(", ", $pgarray);

// This is what pgarray equated to.
// $city, $country

$query  = "Select companyid, city, name from company where 1 = 1 $qclause";
$result = pg_prepare($dbconnect, 'q1', $query);
$runthis = "pg_execute(\$dbconnect, 'q1', array($pgarray) )";


// This is what $runthis equated to.
// pg_execute($dbconnect, 'q1', array($city, $country) )

$result = eval($runthis);

While ..... {
   bla bla bla
}

哦，我也做了

$result = eval('return $runthis');

不会产生任何错误。准备会记录在postgres日志文件中，但pg_execute永远不会发生。

我错过了一些非常明显的东西吗？

由于

JT

Answer 1

已更改

$pgarray[]   = "\$city";
$pgarray[]   = "\$country";

要

$pgarray[]   = $city;
$pgarray[]   = $country;

并且

$runthis = "pg_execute(\$dbconnect, 'q1', array($pgarray) )";

要

$result = pg_execute($dbconnect, 'q1', $pgarray );

它解决了问题，或者我应该说出我的错误代码。

php eval和pg_execute无法正常工作！ ARG

1 个答案: