我有一个使用带有7个标签的UITabBarController的应用。每个选项卡都是一个UIViewController子类(每个都嵌入在UINavigationController中),它在故事板中的视图集中只有不同的背景颜色。 TabItems标记为Tab 1到Tab 7,每个NavBar中的Title集合只是Tab号。我在Info.plist中添加了一些静态Quick Actions,允许我跳转到Tab 2,Tab 3,Tab 6和Tab 7。
我遇到的问题是当我在AppDelegate中处理快速操作时设置选定的Tab时,前4个选项卡的工作正常。如果我选择更多...列表中列出的其中一个选项卡,应用程序只会选择我的UITabBarController中的第一个选项卡。但是,如果应用程序已经运行并且我转到主屏幕并再次尝试快速操作,则可以从更多列表中选择任何选项卡。有什么想法吗?
这是我的AppDelegate代码:
// AppDelegate.swift
import UIKit
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate
{
var window: UIWindow?
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
// Override point for customization after application launch.
// handle quick actions
if let shortcutItem =
launchOptions?[UIApplicationLaunchOptionsKey.shortcutItem]
as? UIApplicationShortcutItem {
let _ = handleShortcut(shortcutItem: shortcutItem)
return false
}
return true
}
func application(_ application: UIApplication, performActionFor shortcutItem: UIApplicationShortcutItem, completionHandler: @escaping (Bool) -> Void) {
completionHandler(handleShortcut(shortcutItem: shortcutItem))
}
private func handleShortcut(shortcutItem: UIApplicationShortcutItem) -> Bool {
let shortcutType = shortcutItem.type
guard let shortcutIdentifier = ShortcutIdentifier(fullIdentifier: shortcutType) else {
return false
}
switch shortcutIdentifier {
case ShortcutIdentifier.OpenTab2: fallthrough
case ShortcutIdentifier.OpenTab3: fallthrough
case ShortcutIdentifier.OpenTab6: fallthrough
case ShortcutIdentifier.OpenTab7:
return selectTabBarItem(forIdentifier: shortcutIdentifier)
}
}
private func selectTabBarItem(forIdentifier identifier: ShortcutIdentifier) -> Bool {
if let tabBarController = self.window?.rootViewController as? CustomTabBarController
{
switch (identifier)
{
case .OpenTab2:
tabBarController.selectedIndex = tabDictionary["OpenTab2"]!
case .OpenTab3:
tabBarController.selectedIndex = tabDictionary["OpenTab3"]!
case .OpenTab6:
tabBarController.selectedIndex = tabDictionary["OpenTab6"]!
case .OpenTab7:
tabBarController.selectedIndex = tabDictionary["OpenTab7"]!
}
}
return true
}
// Integer in dictionary denotes tab number (zero based)
private let tabDictionary = ["OpenTab2": 1, "OpenTab3": 2, "OpenTab6": 5, "OpenTab7": 6]
enum ShortcutIdentifier: String {
case OpenTab2
case OpenTab3
case OpenTab6
case OpenTab7
init?(fullIdentifier: String) {
guard let shortIdentifier = fullIdentifier.components(separatedBy: ".").last else {
return nil
}
self.init(rawValue: shortIdentifier)
}
}
}
答案 0 :(得分:0)
我发现以下链接(http://jakzaprogramowac.pl/pytanie/18417,select-index-greater-than-3-for-uitabbarcontroller-at-app-launch-not-working)似乎回答了我的问题。我希望这有助于其他人。
我将以下代码添加到AppDelegate DidFinishLaunchingWithOptions的开头,以便最初选择第一个选项卡并在tabBarController的视图中调用layoutIfNeeded():
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool
{
// Override point for customization after application launch.
// initially select first tab so more selection works from quick actions - fixup
if let tabBarController = self.window?.rootViewController as? CustomTabBarController
{
tabBarController.selectedIndex = 0
tabBarController.view.layoutIfNeeded()
}
// handle quick actions
if let shortcutItem =
launchOptions?[UIApplicationLaunchOptionsKey.shortcutItem]
as? UIApplicationShortcutItem {
let _ = handleShortcut(shortcutItem: shortcutItem)
return false
}
return true
}