Question

我尝试根据父模型的某些条件（而不是外键）将嵌套的序列化程序添加到现有的序列化程序中。用例是返回一个＆＃39; Research＆＃39;具有＆＃39; ResearchTemplate＆＃39;的数组的对象通过在postgres ArrayField上过滤来识别的对象。

模型


class Research(TimeStampedModel):
    category = models.CharField(max_length=100, choices=RESEARCH_TEMPLATE_CATEGORIES, default='quote')
    body = models.CharField(max_length=1000, blank=True, default='') #The body of text comprising the nugget
    additionaldata = JSONField(null=True) # all the varying values to be merged into a wrapper

    def __str__(self):
        return self.body

    class Meta:
        ordering = ('created',)

class ResearchTemplate(TimeStampedModel):
    template = models.TextField(blank=True, default='')
    category = models.CharField(max_length=100, choices=RESEARCH_TEMPLATE_CATEGORIES, default='quote')
    mergefields = ArrayField(models.CharField(max_length=200), blank=True)

    def save(self, *args, **kwargs):
        merges = re.findall("{{(.*?)}}", self.template) #get all the template names from within the mustaches
        self.mergefields = list(set(merges)) #TODO: Make Unique
        super(TimeStampedModel, self).save(*args, **kwargs)

    def __str__(self):
        return self.wrapper

    class Meta:
        ordering = ('created',)

串行器


class ResearchSerializer(serializers.ModelSerializer):
        templates = ResearchTemplateSerializer(many=True)

        class Meta:
            model = Research
            fields = ('id', 'created', 'speaker', 'body', 'templates')

class ResearchTemplateSerializer(serializers.RelatedField):
        def get_queryset(self, values):
            return ResearchTemplate.objects.filter(mergefields__contained_by=['django']) #This must an array of keys from the Research object's JSON field

        class Meta:
            model = ResearchTemplate
            fields = ('id', 'template')

当有外键映射时，我能够嵌套序列化程序，但无法使用自定义查询集。也许我没有正确地考虑这个问题，我需要某种形式的关系＆＃39;关于研究模型的领域。

如何使用父模型中指定的值嵌套从过滤器返回的所有行的序列化列表？

Answer 1

您可以使用DRF的SerializerMethodField http://www.django-rest-framework.org/api-guide/fields/#serializermethodfield。

将您的ResearchTemplateSerializer定义为普通的ModelSerializer，而不是相关字段。

然后将此ResearchSerializer替换为：

class ResearchSerializer(serializers.ModelSerializer):
    templates = serializers.SerializerMethodField()

    class Meta:
        model = Research
        fields = ('id', 'created', 'speaker', 'body', 'templates')

    def get_templates(self, obj):
        values = obj.get_values() # whatever your filter values are. obj is the Research instance
        templates = ResearchTemplate.objects.filter(mergefields__contained_by=values) # Or whatever queryset filter
        return ResearchTemplateSerializer(templates, many=True).data

Django-Rest-Framework - 如何将不相关模型中的查询集序列化为嵌套序列化程序

1 个答案: