显示存储在数据库中的URL的照片

Question

这是我的数据库：

我试图像这样显示图像

  <?php
$displaymyavatar="SELECT * FROM avatars INNER JOIN users ON avatars.users_id=users.id WHERE username='$login_session'";
 $result_set=mysqli_query($db,$displaymyavatar);
 while($row=mysqli_fetch_array($result_set)){?>
              <img class="avatar" src='<?=$_SERVER['HTTP_REFERER'] . $row['image_file'];?>' alt="">
 <?php };?>

我以为我找到了解决方案here，但图片没有显示。图像上传到文件夹＆＃34;上传＆＃34;

Answer 1

相关链接是否适合您？如果是这样，您应该能够使用以下代码段。

<?php
   $displaymyavatar="SELECT * FROM avatars INNER JOIN users ON avatars.users_id=users.id WHERE username='$login_session'";
   $result_set=mysqli_query($db,$displaymyavatar);
   while($row=mysqli_fetch_array($result_set)){ ?>
       <img class="avatar" src="./<?php echo $row['image_file']; ?>" alt="">
<?php };?>

Answer 2

您可以使用foreach循环

<?php foreach ($result_set as $key => $r): ?>
    <img src="<?php echo $r['image_file'] ?>" />
<?php endforeach ?>

Answer 3

这有效：

     <?php
$displaymyavatar="SELECT * FROM avatars INNER JOIN users ON avatars.users_id=users.id WHERE username='marydoe'";
 $result_set=mysqli_query($db,$displaymyavatar);
 while($row=mysqli_fetch_array($result_set)){?>
              <img class="avatar" src="core/<?php echo $row['image_file'] ?>" />
 <?php };?>