我的主包中(在app目录的根目录下)有一个名为 Data.plist 的文件,我正在尝试将此文件复制到用户文档目录以进行读写操作,但是,在尝试复制文件时出现以下错误:
CFURLCopyResourcePropertyForKey失败,因为它传递了一个没有方案的网址
复制Data.plist时出错:错误域= NSCocoaErrorDomain代码= 262 “无法打开文件,因为指定的URL类型不是 支持的
代码:
let fileManager = FileManager.default
var docDirectory: String? {
let paths = NSSearchPathForDirectoriesInDomains(.documentDirectory, .userDomainMask, true)
let docDir = paths.first
return docDir
}
var dataFilePath: String? {
guard let docPath = self.docDirectory else { return nil }
return docPath.appending("/Data.plist")
}
func copyFile() {
guard let path = dataFilePath else {
return
}
guard fileManager.fileExists(atPath: path) else {
// NSLog("Creating Data.plist")
// fileManager.createFile(atPath: path, contents: nil, attributes: nil) // create the file
// NSLog("created Data.plist file successfully")
if let bundlePath = Bundle.main.path(forResource: "Data", ofType: "plist") {
do {
let fromURL = URL(string: bundlePath)!
let toURL = URL(string: "file://\(path)")!
try fileManager.copyItem(at: fromURL, to: toURL)
NSLog("Copied Data.plist to Document directory")
} catch let error {
NSLog("Error in copying Data.plist: \(error)") // see the above quoted error message from here
}
}
return
}
}
答案 0 :(得分:7)
必须使用fileURLWithPath
初始化程序创建文件系统网址,该初始化程序会添加错误消息所抱怨的file://
方案:
let fromURL = URL(fileURLWithPath: bundlePath)
let toURL = URL(fileURLWithPath: path)
然而,有一种更方便的方法来创建fromURL
:
if let fromURL = Bundle.main.url(forResource: "Data", withExtension: "plist") { ...
我建议通常使用与URL相关的API,例如
var docDirectory: URL {
return try! FileManager.default.url(for: .documentDirectory, in: .userDomainMask, appropriateFor: nil, create: true)
}
var dataFileURL: URL {
return docDirectory.appendingPathComponent("Data.plist")
}
最大的好处是获得非可选值并消除几个guard
s。
答案 1 :(得分:0)
检查XCODE项目中的文件Data.plist是否存在。