Question

我正在使用的代码是：

DECLARE @var1 AS int;
SET @var1=8191;
WITH A AS (
    SELECT 0 AS ORD, @var1 AS NUMBER, CAST('' AS VARCHAR(20)) AS BITS
    UNION ALL
    SELECT ORD+1, NUMBER/2,  CAST(BITS+CAST(NUMBER%2 AS VARCHAR(20)) AS VARCHAR(20))
          FROM A
          WHERE  NUMBER>0)
SELECT RIGHT('000000000000000'+ CASE WHEN BITS='' THEN '0' ELSE REVERSE(BITS) END,16) AS BIN_VALUE 
FROM A
WHERE NUMBER=0

这得到存储在@ Var1中的数字的二进制值，所以对于8191，它会给出结果0001111111111111，我想捕获该数字，所以我可以在另一个查询中使用它，例如在@ Var2中。非常感谢任何帮助。

Answer 1

这不适合你吗？

SELECT @var2 = RIGHT('000000000000000'+ CASE WHEN BITS='' THEN '0' ELSE REVERSE(BITS) END,16) 
FROM A
WHERE NUMBER = 0;

Answer 2

试试这个...我添加了Declare @Var2，在最后的选择中我添加了SELECT @Var2 =位。

DECLARE @Var2 AS VARCHAR(50) -- or whatever data type you need

DECLARE @var1 AS int;    
SET @var1=8191;
WITH A AS (
SELECT 0 AS ORD, @var1 AS NUMBER, CAST('' AS VARCHAR(20)) AS BITS
UNION ALL
SELECT ORD+1, NUMBER/2,  CAST(BITS+CAST(NUMBER%2 AS VARCHAR(20)) AS VARCHAR(20))
      FROM A
      WHERE  NUMBER>0)
SELECT @Var2 = RIGHT('000000000000000'+ CASE WHEN BITS='' THEN '0' ELSE     REVERSE(BITS) END,16) AS BIN_VALUE 
FROM A
WHERE NUMBER=0

Answer 3

没有递归CTE的另一种方式

DECLARE @var1 AS SMALLINT = 8191,
        @Var2 CHAR(16);

SELECT @Var2 = 
RIGHT('000000000000000'+ 
 REPLACE(
  REPLACE(
   REPLACE(
    REPLACE(
     REPLACE(
      REPLACE(
       REPLACE(
        REPLACE(
         REPLACE(
          REPLACE(
           REPLACE(
            REPLACE(
             REPLACE(
              REPLACE(
               REPLACE(
                REPLACE(
                 FORMAT(@var1,'x')
                ,'0','0000')
               ,'1','0001')
              ,'2','0010')
             ,'3','0011')
            ,'4','0100')
           ,'5','0101')
          ,'6','0110')
         ,'7','0111')
        ,'8','1000')
       ,'9','1001')
      ,'a','1010')
     ,'b','1011')
    ,'c','1100')
   ,'d','1101')
  ,'e','1110')
 ,'f','1111')
,16)

SELECT @Var2

尝试将选择查询的结果捕获到变量中但得到语法错误

3 个答案: