Question

我想在猜测游戏结束时添加一些代码，询问用户是否想再玩一次。如果他们说是，我想，该计划将从一开始就再次运行。我尝试过多种想法，但都没有。最接近的是最后的另一个if循环。谢谢！ X

print("Welcome to this guessing game!")

import random

x = random.randrange(50)

guess = int(input("I've picked an integer between 1 to 99. Guess what it is: "))

while x != "guess":

print
if guess < x:
    print("Your guess is too low!")
    guess = int(input("Guess again:"))
elif guess > x:
    print("Your guess is too high!")
    guess = int(input("Guess again:"))
else:
    print ("You guessed the right number!")

Answer 1

类似的东西：

while True:
    your code

    if input("Continue? Y/N: ").lower() not in {"y", "yes"}:
        break

在每次播放结束时，这会从用户那里获得输入，将其转换为小写，并查看它是否＆＃34; y＆＃34;或＆＃34;是＆＃34;。如果不是，则游戏突然退出，即退出。否则它会继续循环。

Answer 2

您可以将游戏包装在一个功能中。然后在用户说“是”时，您调用该函数。在游戏结束时，重新考虑同样的问题。

这是为什么功能。

伪代码：

   function askUser(){
    'Do you want to play'=>yes: launchGame, no:print("ok bye bye")
    }

    function myGame(){
    //your game
        askUser()
    }

Answer 3

例如

import random
something="yes"

while(something == "yes"):
#your code...
#....
#from your code
else:
    print ("You guessed the right number!")
    something=input("Do you want to play again? (yes/no)")#input return str? I use raw_input all the time in p2.7

和此：

while x != "guess":

为什么要猜测使用＆＃34; ＆＃34;

x = random.randrange（50）所以x永远不是一个字符串＆＃34; guess＆＃34;它与True相似：或者1：

Answer 4

print("Welcome to this guessing game!")

import random

x = random.randrange(50)

guess = int(input("I've picked an integer between 1 to 99. Guess what it is: "))

while True:

    if guess < x:
        print("Your guess is too low!")
        guess = int(input("Guess again:"))
    elif guess > x:
        print("Your guess is too high!")
        guess = int(input("Guess again:"))
    else:
        print ("You guessed the right number!")
        break

您正在了解python的基础知识，因此没有太多建议来阅读更多书籍 x是int的类型并猜测你使用“”包括“猜测”他不是变量名并成为字符串

我如何让这个Python猜测游戏重新开始？

4 个答案: