Question

我有一个由StrainGmoType继承的主窗体（StrainType），而StrainGmoType嵌入了一个StrainPlasmidType。

在主窗体（StrainType）中，我有一个用户选择团队的字段，然后一些字段取决于这个选择（在main，child和embded表单中）。对于在主窗体或子窗口中声明的所有字段，它都有效。但是我有2个CollectionType，在这个CollectionType中我有很多与参数的关系。然后我做了一个特定的Type（StrainPlasmidType），在main和child类型中，我在CollectionType中调用它们（在示例中只在子节点中））。但是，我无法获得此类型的团队字段，那么我不能做PRE_SET_DATA，PRE_SUBMIT或POST_SUBMIT ......

我尝试使用inherit_data，但它并不适合这种情况。如何获取StrainPlasmidType中团队字段的数据？

代码的一部分：

The StrainForm：

  class StrainType extends AbstractType
  {
      public function buildForm(FormBuilderInterface $builder, array $options)
      {
          $builder
              ->add('team', EntityType::class, [
                  'class' => 'AppBundle\Entity\Team',
                  'query_builder' => function (EntityRepository $er) {
                      return $er->createQueryBuilder('team')
                          ->leftJoin('team.members', 'members')
                          ->leftJoin('team.projects', 'projects')
                          ->leftJoin('projects.members', 'project_members')
                          ->where('members = :user')
                          ->orWhere('project_members = :user')
                          ->setParameter('user', $this->tokenStorage->getToken()->getUser());
                  },
                  'data' => $this->tokenStorage->getToken()->getUser()->getFavoriteTeam(),
                  'choice_label' => 'name',
                  'placeholder' => '-- select a team --',
                  'mapped' => false,
              ])

GmoStrain表格：

  class StrainGmoType extends AbstractType
  {
      public function buildForm(FormBuilderInterface $builder, array $options)
      {
          $builder
              ->add('strainPlasmids', CollectionType::class, [
                  'entry_type' => StrainPlasmidType::class,
                  'allow_add' => true,
                  'allow_delete' => true,
                  'by_reference' => false,
                  'required' => false,
              ])

              //...

        public function configureOptions(OptionsResolver $resolver)
        {
            $resolver->setDefaults([
                'data_class' => 'AppBundle\Entity\Strain',
            ]);
        }

        public function getParent()
        {
            return StrainType::class;
        }
    }

StrainPlasmidType：

  class StrainPlasmidType extends AbstractType
  {
      public function buildForm(FormBuilderInterface $builder, array $options)
      {
          $builder
              ->add('plasmid', EntityType::class, [
                  'class' => 'AppBundle\Entity\Plasmid',
                  'query_builder' => function (EntityRepository $er) {
                      return $er->createQueryBuilder('p')
                          ->leftJoin('p.team', 'team')
                          ->leftJoin('team.members', 'members')
                          ->where('members = :user')
                          ->setParameter('user', $this->tokenStorage->getToken()->getUser())
                          ->orderBy('p.autoName', 'ASC')
                      ;
                  },
                  'group_by' => function (Plasmid $plasmid) {
                      return $plasmid->getTeam()->getName();
                  },
                  'choice_label' => function (Plasmid $plasmid) {
                      return $plasmid->getAutoName().' - '.$plasmid->getName();
                  },
                  'placeholder' => '-- select a plasmid --',
              ])
              ->add('state', ChoiceType::class, [
                  'choices' => [
                      'Replicative' => 'replicative',
                      'Integrated' => 'integrated',
                      'Cured' => 'cured',
                  ],
                  'placeholder' => '-- select a state --',
              ])
          ;

Answer 1

最后，我只使用表单选项将数据发送到嵌入表单：

主要：

  $form->add('strainPlasmids', CollectionType::class, [
      'entry_type' => StrainPlasmidType::class,
      'entry_options' => [
          'parent_data' => $team,
      ],
      'allow_add' => true,
      'allow_delete' => true,
      'by_reference' => false,
      'required' => false,
  ]);

并且，以嵌入形式：

  public function buildForm(FormBuilderInterface $builder, array $options)
  {
      $builder
          ->add('plasmid', EntityType::class, [
              'class' => 'AppBundle\Entity\Plasmid',
              'query_builder' => function (EntityRepository $er) use ($options) {
                  return $er->createQueryBuilder('p')
                      ->leftJoin('p.team', 'team')
                      ->where('team = :team')
                      ->setParameter('team', $options['parent_data'])
                      ->orderBy('p.autoName', 'ASC')
                  ;
              },

  public function configureOptions(OptionsResolver $resolver)
  {
      $resolver->setDefaults([
          'data_class' => 'AppBundle\Entity\StrainPlasmid',
      ]);

      $resolver->setRequired(array('parent_data'));
  }

Symfony：具有嵌入形式的动态形式

1 个答案: