如何使用numpy savetxt将复杂数据保存为行？

Question

如何以下列格式保存复杂数据？

0.0001760855-0.0000927256j
-0.0002311308+0.0000122892j
0.0002447444+0.0000968709j
-0.0002038497-0.0002121365j
0.0001077393+0.0003059170j
0.0000306011-0.0003521998j
-0.0001864669+0.0003330580j
0.0003283114-0.0002435598j
-0.0004244564+0.0000938909j
0.0004501374+0.0000918577j

但是使用numpy.savetxt（“path_to_array”，数组）我有这个：

(1.760855000000000135e-04+-9.272560000000000546e-05j)
 (-2.311307999999999928e-04+1.228919999999999916e-05j)
 (2.447444000000000008e-04+9.687089999999999438e-05j)
 (-2.038497000000000009e-04+-2.121365000000000110e-04j)
 (1.077393000000000003e-04+3.059170000000000053e-04j)
 (3.060110000000000082e-05+-3.521997999999999817e-04j)
 (-1.864668999999999951e-04+3.330580000000000086e-04j)
 (3.283113999999999954e-04+-2.435597999999999919e-04j)
 (-4.244564000000000041e-04+9.389090000000000597e-05j)
 (4.501374000000000044e-04+9.185770000000000653e-05j)

请注意“（），+ - ，e-04”

Answer 1

试试这个：

complex_array = [complex(0.0001760855-0.0000927256j),
complex(-0.0002311308+0.0000122892j),
complex(0.0002447444+0.0000968709j),
complex(-0.0002038497-0.0002121365j),
complex(0.0001077393+0.0003059170j)]

np.savetxt('tmp.txt', complex_array, fmt='%.10f%+.10fj')

tmp.txt：

0.0001760855-0.0000927256j
-0.0002311308+0.0000122892j
0.0002447444+0.0000968709j
-0.0002038497-0.0002121365j
0.0001077393+0.0003059170j