Question

我正在尝试修改.html页面中按钮的行为，更确切地说，我有：

<input id="next" name="signIn" class="rc-button rc-button-submit" type="submit" value="Next">

我想获得：

<input id="next" name="signIn" class="rc-button rc-button-submit"  value="NEXT" Onclick="window.location.href='http://www.some_web_page.com/'">

使用bs4可以做到这一点吗？到目前为止，我设法识别html页面中所需的部分，但我不确定如何才能进行更改：

page=requests.get('https://www.some_page.com/') soup = BeautifulSoup(page.content, 'html.parser') print (soup.findAll(id="next"))

由于

Answer 1

In [44]: html = '''<input id="next" name="signIn" class="rc-button rc-button-submit" type="submit" value="Next">'''

In [45]: soup = BeautifulSoup(html, 'lxml')

In [46]: soup.input['Onclick'] = "window.location.href='http://www.some_web_page.com/'"

In [47]: soup
Out[47]: <html><body><input Onclick="window.location.href='http://www.some_web_page.com/'" class="rc-button rc-button-submit" id="next" name="signIn" type="submit" value="Next"/></body></html>

Python Beautiful Soup修改onclick事件属性

1 个答案: