Question

我试图从表单验证一些登录信息。安全性并不重要，因为这对我的朋友和我来说只是一个小小的社交媒体，我有备份，所以我不介意被黑客入侵，我只是在学习php。

以下是我遇到的错误：

致命错误：在非对象上调用成员函数fetch_assoc（）在/srv/disk4/2177948/www/website.com/postlogin.php第34行

这是代码：第34行标有//

注意：连接信息已被删除，它在脚本中运行良好。

<?php

session_start();

$usrName = $_POST['logInName'];
$pass = $_POST['logInPass'];
$servername = "censored";
$username = "censored";
$password = "censored";
$db_name = "censored";
$conn = mysqli_connect($servername, $username, $password, $db_name);

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT usrName FROM loginInfo WHERE usrName='" . $usrName . "';";
$result = mysqli_query($conn,$sql);

if ($conn->query($sql) == TRUE) {
    while ($row = $result->fetch_assoc()) {
        $retrievedUsrName = $row["usrName"];
    }
} else {
    echo 'Error: ' . $conn->error;
}

$result->free;

if ($retrievedUsrName == $usrName) {
    $sql2 = "SELECT pw FROM logininfo WHERE pw='" . $pass . "';";
    $result2 = mysqli_query($conn,$sql2);

    while ($row = $result2->fetch_assoc()) { //Line 34
        $retrievedPass = $row["pw"];
    }
} else {
    echo 'Fant ikke brukernavnet i databasen. Spør Tommy.';
}

if ($retrievedPass == $pass) {
    header('Location: index.php');
} else {
    echo 'Fant ikke passordet i databasen. Spør Tommy.';
}

$result->free;

$conn->close;

?>

致命错误：在第34行

0 个答案: