Question

我有一些看起来像这样的嵌套迭代器：

line_count = 1
if commit.body.lines.each do |line|
  unless @diff_line_nums.include? line_count
     puts line
  else
     filtered_diffs.each do |diff|
         diff.body.lines.each do |line|
             puts line
         end
     end
   end
  line_count += 1
end

简单来说，这就是我当前版本中发生的情况：

a      line_count = 1
b      line_count = 2
c -    line_count = 3
   1
   2
   3
d      line_count = 4
e -    line_count = 5
   1
   2
   3
   4
   5
f      line_count = 6
g      line_count = 7
h      line_count = 8
i      line_count = 9
j      line_count = 10

然而，我想要发生的是：

a      line_count = 1
b      line_count = 2
c -    line_count = 3
   1
   2
   3
   4
h      line_count = 8
i      line_count = 9
j -    line_count = 10
   1
   2
   3
n     line_count = 14
o     line_count = 15
p     line_count = 16

Aka ....当它在外部块中迭代时，一旦它进入内部迭代并成功处理每个项目，在内部的每次成功迭代时它也应该自动增加外部。

Answer 1

您可以使用第二个变量来保存其他计数器。像这样：

line_count = 1
shifted_line_count = 0

if commit.body.lines.each do |line|
  unless @diff_line_nums.include? line_count
     puts line + shifted_line_count
  else
     filtered_diffs.each do |diff|
         diff.body.lines.each do |line|
             shifted_line_count += 1
             puts line
         end
     end
   end
  line_count += 1
end

当嵌套迭代中的步骤正常跳过时，如何跳过父迭代步骤？

1 个答案: