目前我正在编写一个与ArangoDB交互的程序
有没有办法使用libcurl以JSON格式发送HTTP put请求?
我目前在curl中的命令是
curl -X PUT --data-binary @- --dump - --user "root:" http://localhost:8529/_db/myapp1/_api/simple/lookup-by-keys << EOF {"keys" : [ "FirstUser" ], "collection" : "five"} EOF
我想知道上面发送请求的等效libcurl代码。感谢
答案 0 :(得分:1)
//PUT Request
#include <stdio.h>
#include <string.h>
#include <curl/curl.h>
int main(int argc, char const *argv[]){
CURL *curl;
CURLcode res;
long http_code;
static const char *jsonObj = //insert json here
curl = curl_easy_init();
curl_global_init(CURL_GLOBAL_ALL);
if(curl){
curl_easy_setopt(curl, CURLOPT_URL, "//insert your url here");
curl_easy_setopt(curl, CURLOPT_HTTPAUTH, (long)CURLAUTH_BASIC);
curl_easy_setopt(curl, CURLOPT_USERPWD, "root:");
curl_easy_setopt(curl, CURLOPT_CUSTOMREQUEST, "PUT");
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, jsonObj);
//enable to spit out information for debugging
//curl_easy_setopt(curl, CURLOPT_VERBOSE,1L);
res = curl_easy_perform(curl);
if (res != CURLE_OK){
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res) );
}
printf("\nget http return code\n");
curl_easy_getinfo(curl, CURLINFO_RESPONSE_CODE, &http_code);
printf("http code: %lu\n", http_code );
curl_easy_cleanup(curl);
curl_global_cleanup();
}
return 0;
}
这是我提出的解决方案。请随意添加/改进