Question

我正在将我的应用更新为Swift 3，并使用Alamofire处理对REST服务器的API调用。这是我的功能：

extension Alamofire.Request {
    func responseAllCareers(_ username: String, password: String, completionHandler: @escaping (DataResponse<Careers>) -> Void) -> Self {
        let responseSerializer = DataResponseSerializer<Careers> { request, response, data, error in

            guard error == nil else {
                return .failure(BackendError.network(error: error!))
            }

            let JSONResponseSerializer = DataRequest.jsonResponseSerializer(options: .allowFragments)
            let result = JSONResponseSerializer.serializeResponse(request, response, data, error)

            guard case let .success(jsonObject) = result else {
                return .failure(BackendError.jsonSerialization(error: result.error!))
            }

            switch result {
            case .success(let value):
                let api: APIMessage = APIMessage(json: value as! JSON)!
                var careers: Careers = Careers()

                // check for correct credentials
                if api.result != "failure" {
                    careers = Careers(json: value as! JSON)
                    CacheManager.sharedInstance.storeCredentials(username, password: password)
                    CacheManager.sharedInstance.storeJsonInCacheByKey(CacheManager.CAREERS, json: value as! JSON)
                    careers.areCredentialsValid = true
                }
                return .success(careers)
            case .failure(let error):
                return .failure(error)
            }
        }
        return response(responseSerializer: responseSerializer, completionHandler: completionHandler)
    }

我收到无法在最后一个返回行调用非函数类型'HTTPURLResponse'错误的值，我无法弄清楚原因。

Answer 1

您尝试使用值而不是类型

来初始化响应

response(responseSerializer: responseSerializer, completionHandler: completionHandler)

其中实际response是实例化的常量。第二个问题是该函数应该返回Alamofire.Request类型，而不是HTTPURLResponse类型。

Alamofire 4 - 无法调用非功能类型HTTPURLResponse的值

1 个答案: