我想在以下代码中访问数组中的单个数组值
现在结果:
{"result":[{"msgno":" 1","from":[{"personal":"Blind Mailer","mailbox":"mailerblind","host":"gmail.com"}],"subject":"Testing","date":"Mon, 2 Jan 2017 13:16:21 +0530"}]}
必填结果:
{"result":[{"msgno":" 1","from":"Blind Mailer","subject":"Testing","date":"Mon, 2 Jan 2017 13:16:21 +0530"}]}
php代码:
$emails = imap_search($inbox,'SEEN');
$output = '';
$result=array();
foreach($emails as $ove) {
$headerInfo = imap_headerinfo($inbox,$ove);
$emailStructure = imap_fetchstructure($inbox,$ove);
if(!isset($emailStructure->multipart)) {
array_push($result,array("msgno"=>$headerInfo->Msgno ,"from"=>$headerInfo->from,"subject"=>$headerInfo->subject,"date"=>$headerInfo->date));
} else {
array_push($result,array("msgno"=>$ove->msgno,"from"=>$ove->from,"subject"=>$ove->subject,"date"=>$ove->date));
}
}
echo json_encode(array('result'=>$result));
答案 0 :(得分:0)
array_push
会将项目附加到数组中。由于你追加的是一个数组,你在一个数组中有一个数组而不是一个数组中的所有值。
相反,您希望使用array_merge
,它将采用两个数组并将它们连接在一起以创建单个1维数组。请参阅PHP手册:http://php.net/manual/en/function.array-merge.php