Question

Ajax响应我得到的结果如下：

"students":[{
"student_id":"27",
"job_id":"12",
"128":"8",
"63":"9",
"3":"10",
"weightage":"5.6000"}
,{"student_id":"22",
"job_id":"12",
"128":"5",
"63":"6",
"3":"8",
"weightage":"9.1000"
}]}

由此我想显示相同的顺序，因为权重（总分）很高，它应该在最后一个较小的一个。

如何按描述过滤？这是我的代码：

console.log(response['students']);
$.each(response['students'], function(k, student) {                 
    $("#stu"+student.student_id).removeClass('btn-danger reject-student');                  
    $("#stu"+student.student_id).addClass('btn-success select-student');                    
    $("#stu"+student.student_id).text('Student Selected');                  
});             
/*Sorting select-student students at one place starts here*/                
var rows = document.querySelectorAll('table tbody tr.sorted');              
for (i = 0; i < rows.length; i++) {                 
    if (rows[i].querySelector('span.reject-student')) {                     
        rows[i].closest('tbody').appendChild(rows[i]);                      
    }                   
}               
/*Sorting select-student students at one place ends here*/

Answer 1

这很简单。将响应JSON字符串解析为对象。请尝试以下方法：

// Array of student objects
var students = JSON.parse("Your response json string");

//Sort this array by weightage property in descending order
students.sort(function(a,b){
   return b.weightage - a.weightage; // descending order
});

见下面的小提琴：

var response = '[{"student_id": "27","job_id": "12","128": "8","63": "9","3": "10","weightage": "5.6000"}, {"student_id": "22","job_id": "12","128": "5","63": "6","3": "8","weightage": "9.1000"}]';

var students = JSON.parse(response);

students.sort(function(a,b){
   return b.weightage - a.weightage; // descending order
});

alert(students[0].weightage);
alert(students[1].weightage);

希望这会有所帮助：）

Answer 2

var rows = document.querySelectorAll('table tbody tr.sorted');      
$.each(response['students'], function(k, student) {     
    $("#stu"+student.student_id).removeClass('btn-danger reject-student');                  
    $("#stu"+student.student_id).addClass('btn-success select-student');                    
    $("#stu"+student.student_id).text('Student Selected');  
    /*  Sorting by student overall score starts here   */
    for (i = 0; i < rows.length; i++) {                 
        if (rows[i].querySelector('span#stu'+student.student_id)) {                     
            rows[i].closest('tbody').appendChild(rows[i]);                      
        }                   
    }
    /*  Sorting by student overall score ends here   */
});

如何在ajax响应后通过Javascript中的Desc进行过滤

2 个答案: