我需要确定一些链接子代码的主父代码,但我不断收到最大递归错误。我还是SQL的新手,所以有人可以帮我解决这个问题。
理想情况下,我希望最终结果看起来像这样:
Code I我一直在玩这样的:
WITH Hierarchy(Code, Previous_Code, Master_Parent)
AS
(
SELECT CAST(Code AS VARCHAR(MAX)), CAST(Previous_Code AS VARCHAR(MAX)), CAST('' AS VARCHAR(MAX))
FROM Test AS LastGeneration
WHERE CAST(Code AS VARCHAR(MAX)) NOT IN (SELECT COALESCE(CAST(Previous_Code AS VARCHAR(MAX)), '0') FROM Test)
UNION ALL
SELECT CAST(PrevGeneration.Code AS VARCHAR(MAX)), CAST(PrevGeneration.Previous_Code AS VARCHAR(MAX)),
CAST(CASE WHEN Child.Previous = ''
THEN(CAST(Child.Code AS VARCHAR(MAX)))
ELSE(Child.Previous + '.' + CAST(Child.Code AS VARCHAR(MAX)))
END AS VARCHAR(MAX))
FROM Test AS PrevGeneration
INNER JOIN Hierarchy AS Child ON PrevGeneration.Code = Child.Previous_Code
)
SELECT *
FROM Hierarchy
OPTION(MAXRECURSION 32767)
答案 0 :(得分:1)
<?php
header('Content-type: application/json');
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "jammer";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
header('HTTP/1.1 500 Bad connection to Database');
die("The server is down, we couldn't establish the DB connection");
}
else {
$conn ->set_charset('utf8_general_ci');
$userName = $_POST['username'];
$userPassword = $_POST['userPassword'];
$sql = "SELECT username, firstName, lastName FROM users WHERE username = '$userName' AND password = '$userPassword'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$response = array('firstName' => $row['firstNameName'], 'lastName' => $row['lastName']);
}
echo json_encode($response);
}
else {
header('HTTP/1.1 406 User not found');
die("Wrong credentials provided!");
}
}
$conn->close();
?>
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