Question

我很想在django rest框架中开发API。我想为app mobile创建API。

该服务具有以下功能：

如果通过邮件找不到新用户
显示用户的所有数据（如果已找到）。

型号：

class Users(models.Model):
    sync_id = models.BigIntegerField(primary_key=True)
    points = models.IntegerField()
    phone = models.CharField(max_length=50, blank=True, null=True)
    email = models.CharField(max_length=50, blank=True, null=True)

    def __unicode__(self):
        return self.sync_id

    def save(self, *args, **kwargs):
        sequence_name = 'SEQ_ID'
        # Query the database for the next sequence value.
        from django.db import connection
        cursor = connection.cursor()
        cursor.execute("SELECT %s.nextval FROM DUAL;" % (sequence_name))
        row = cursor.fetchone()
        self.sync_id = row[0]
        return super(Users, self).save(*args, **kwargs) 

    class Meta:
        managed = False
        db_table = 'users'
        unique_together = (('email'),)

查看：

def users_detail_email(request, email):
    try:
        users = Users.objects.filter(email=email)
    except Users.DoesNotExist:
        return Response(status=status.HTTP_404_NOT_FOUND)

    if request.method == 'GET':
        serializer = UsersSerializer(users, many=True)
        return Response(serializer.data)

我已经编写了用于显示用户的所有数据的API代码。但如果找不到它，我需要帮助才能创建它

我尝试在视图中添加以下代码，但它没有保存任何内容

 try:
        users = Users.objects.filter(email=email)
    except Users.DoesNotExist:
        context= {"sync_id": 99999999, "points": 0, "phone": "","email": email}
        serializer = UsersSerializer(data=context.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

Answer 1

将字典传递给UserSerializer：

serializer = UsersSerializer(data=context)

如果你打电话给那些不存在的东西，我就不知道它应该如何工作。你没有带回溯的500错误吗？

如何在Django REST Framework中的异常时创建新数据

1 个答案: