Question

我知道如何使用while循环，但我不确定我需要发出命令来加倍前一个分数的部分。

任务是加倍或退出。

这是我目前的代码：

toHaveBeenCalled()

Answer 1

无需定义新的var newnumber，只需重写Original 通过original = original*2

import random
play = 'y'
original = 1
while play.lower() == 'y':
    chance = random.randint(0,3)
    if chance == 0:
        print("Unlucky.... better luck next time")
    else:
        original = original*2
        print (original)  
    play = input("Play again?[y/n]: ")

Answer 2

无需引入变量newnumber。另外，不要使用大小写变量的混合。

import random
play = 'y'
original = 1
while play.lower() == 'y':
    chance = random.randint(0,3)
    if chance == 0:
        print("Unlucky.... better luck next time")
    else:
        original= original*2 # or shorthand: original *= 2
        print (original)  
    play = input("Play again?[y/n]: ")

Answer 3

如果您尝试将newNumber变量加倍，则无需将Original = Original * 2置于混合中。只是用 Original *= 2（简称$res = $client->request('POST', 'https://fghfgh', [ 'auth' => ['user', 'pw'], 'headers' => [ 'Content-Type' => 'application/json', 'Accept' => 'application/json', ] ]);）。

Answer 4

您将新变量值(original * 2)分配给循环的本地范围变量，因此每次迭代original仍为1.

import random
play = 'y'
original = 1
while play.lower() == 'y':
    if (random.randint(0, 3) == 0):
        print('Unlucky... better luck next time')
    else:
        original *= 2; print(original)
    play = input('Play again? [y/n]: ')

双循环或退出/循环

4 个答案: