Question

我正在使用django-filter在django中显示我的结果

但是我必须根据模型中的属性过滤一些结果我还要使用列表理解

def extra_available_list(request):
    EXTEND = "rent_base.html"
    extra_list_gen = ExtraFilter(request.GET, queryset=Extra.objects.all().order_by('is_parking'))
    extra_list = [obj for obj in extra_list_gen if ((obj.lease)==0)]

    paginator = Paginator(extra_list, 10) # Show 25 contacts per page

    page = request.GET.get('page')
    try:
        extra_page = paginator.page(page)
    except PageNotAnInteger:
        # If page is not an integer, deliver first page.
        extra_page = paginator.page(1)
    except EmptyPage:
        # If page is out of range (e.g. 9999), deliver last page of results.
        extra_page = paginator.page(paginator.num_pages)

    return render(request,'unit/extra_list.html', {'extra': extra_list,'page_extra':extra_page})

如何将列表推导的输出合并到我的django过滤器中？

更新

我尝试过建议的解决方案

extra_list_gen = Extra.objects.all（） extra_list_ids = [obj for obj in extra_list_gen if（（obj.lease）== 0）] extra_list = ExtraFilter（request.GET，queryset = Extra.objects.filter（id__in = extra_list_ids）.order_by（＆＃39; is_parking＆＃39;））

但是我收到了错误

int（）参数必须是字符串或数字，而不是＆＃39;额外＆＃39;
            extra_list = ExtraFilter(request.GET, queryset=Extra.objects.filter(id__in=extra_list_ids).order_by('is_parking'))

Answer 1

因为你需要一个查询集，你可以做这样的事情

# First get the ids that you want, saving the id to the list
extra_objects_ids = [obj.id for obj in Extra.objects.all() if ((obj.lease)==0)]

# Now filter using id__in and then order
extra_queryset = Extra.objects.filter(id__in=extra_objects_ids).order_by('is_parking')

如何在django-filter中包含列表理解结果？

1 个答案: