Question

我有以下SQL查询：

return User::where("users.id", $id)
            ->select(array('rating.rate', User::raw('count(offers.id) AS ofrs, count(announcements.id) as appts')))
            ->join('announcements', 'users.id', '=', 'announcements.user_id')
            ->join('offers', 'users.id', '=', 'offers.user_id')
            ->join('rating', 'users.id', '=', 'rating.user_id')
            ->group_by('ofrs')
            ->get();

它给了我一个错误：

Builder.php第2508行中的BadMethodCallException：调用undefined 方法Illuminate \ Database \ Query \ Builder :: group_by（）

为什么不按分组工作？

同样我尝试的方式：

  return User::where("users.id", $id)
            ->selectRaw('rating.rate, count(offers.id) AS ofrs, count(announcements.id) as appts')
            ->groupBy('appts')
            ->groupBy('ofrs')
            ->join('announcements', 'users.id', '=', 'announcements.user_id')
            ->join('offers', 'users.id', '=', 'offers.user_id')
            ->join('rating', 'users.id', '=', 'rating.user_id')
            ->get();

结果：

SQLSTATE[42000]: Syntax error or access violation: 1056 Can't group on 'appts'

我在SQL中直接编写了SQL查询：

select rating.rate, COUNT(offers.id) AS ofrs, COUNT(announcements.id) as appts from `users` left join `announcements` on `users`.`id` = `announcements`.`user_id` left join `offers` on `users`.`id` = `offers`.`user_id` left join `rating` on `users`.`id` = `rating`.`user_id` where `users`.`id` = 1

它有效，按型号不是：

return User::where("users.id", $id)
            ->selectRaw('rating.rate, COUNT(offers.id) AS ofrs, COUNT(announcements.id) as appts')
            ->leftJoin('announcements', 'users.id', '=', 'announcements.user_id')
            ->leftJoin('offers', 'users.id', '=', 'offers.user_id')
            ->leftJoin('rating', 'users.id', '=', 'rating.user_id')
            ->get();

这项工作：

return User::where("users.id", $id)
            ->selectRaw('rating.rate, COUNT(offers.id) AS ofrs, COUNT(announcements.id) AS appts')
            ->leftJoin('announcements', 'users.id', '=', 'announcements.user_id')
            ->leftJoin('offers', 'users.id', '=', 'offers.user_id')
            ->leftJoin('rating', 'users.id', '=', 'rating.user_id')
            ->groupBy('rating.rate')
            ->get();

Answer 1

您呼叫分组依据的功能名称不正确。尝试：

->groupBy('ofrs')

有关详情，请参阅here。

Answer 2

您需要了解SQL的工作原理。您无法按计数别名进行分组。您正在寻找的可能是三个查询或三个关系。

您应该在用户上为公告创建关系，第二个用于提供，第三个用于评级。

比您User::find($id)->announcements->count()，User::find($id)->offers->count()和User::find($id)->ratings->count()

或者您可以使用您的Fluent方式：

return User::find($id) ->leftJoin('announcements', 'users.id', '=', 'announcements.user_id') ->count();

为什么不能使用SQL查询Laravel？

2 个答案: