Question

我有像这样的json回复

    [{
    "id": 94973,
    "slug": "la-liga-real-betis-1-1-barcelona-29-januari-2017",
    "title": {
        "rendered": "La Liga: Real Betis 1-1 Barcelona 29 Januari 2017"
    }
}, {
    "id": 94957,
    "slug": "fa-chelsea-4-0-brentford-28-januari-2017",
    "title": {
        "rendered": "FA: Chelsea 4-0 Brentford, 28 Januari 2017"
    }
}, {
    "id": 94944,
    "slug": "serie-a-ac-milan-1-2-napoli-22-januari-2017",
    "title": {
        "rendered": "Serie A: AC Milan 1-2 Napoli, 22 Januari 2017"
    }
}]

我想要做的是获取渲染标题的值而不是id和slug

这是我的改装课程

            public void onResponse(Call<List<Coba>> call, Response<List<Coba>> response) {
            try {
                List<Coba> jsonResponse = response.body();
                data= new ArrayList<>();
                data.addAll(jsonResponse);
                adapter = new MyAdapter(data);
                adapter.notifyDataSetChanged();
                recyclerView.setAdapter(adapter);
                Log.i("HASIL", "onResponse: "+data);
            }catch (Exception e) {
                Log.d("onResponse", "There is an error");
                e.printStackTrace();
            }
        }

如何使用retfrofit获取该值？

Answer 1

创建一个类

public class CobaResponse { 
    Arraylist<Coba> cobas;
    getCobas(){ return cobas; }

    class Coba {
        int id;
        String slug;
        Map<String,String> title;

        getId(){ return id; }
        getSlug(){ return slug; }
        getMap(){ return title; }
    }
}

在改造界面中使用该模型。

@Get("/requesturl")
Call<CobaResponse> getCobas();

最后onResponse方法。

Response.body().getCobas.get(0).getId();

阵列改造中的JSON对象

1 个答案: