Question

我导入regex以获取字符串中的字数，并且我尝试使用^运算符。虽然，编译器将^识别为正则表达式的一部分，而不是独占或运算符。这是我的代码：

import re as regex

count = len(regex.findall(r'\w+', question))


if count < 3:

    magicball.say("No Spam Allowed!!")

elif "will" in question ^ "can" in question ^ "did" in question ^ "is" in question ^ "do" in question ^ "are" in question ^ "has" in question ^ "does" in question ^ "is" in question:

    verified = True
    print(oringinalquestion)

我收到错误的行是elif。基本上，有没有办法告诉编译器我想使用独占或运算符？提前谢谢！

Answer 1

如果你可以添加错误跟踪，那就太好了。我怀疑你需要在每个布尔语句上加上括号，如下所示：

elif ("will" in question) ^ ("can" in question) ^ ("did" in question) ^ ("is" in question) ^ ("do" in question) ^ ("are" in question) ^ ("has" in question) ^ ("does" in question) ^ ("is" in question):

Answer 2

运算符^的优先级高于运算符in。你的表达式相当于"will" in (question ^ "can") in (question ^ "did") ...，而你可能想要它("will" in question) ^ ("can" in question) ^ ("did" ...。因此，请使用括号来消除表达式的歧义。

Python - 与正则表达式以及独占或运算符冲突

2 个答案: