如果我有以下Python类:
class Test(object):
funcs = {
"me" : "action",
"action": "action",
"say" : "say",
"shout" : "say"
}
def dispatch(self, cmd):
def say:
print "Nested Say"
def action:
print "Nested Action"
# The line below gets the function name as a string,
# How can I call the nested function based on the string?
Test.funcs.get(cmd, "say")
我希望能够做到以下几点:
>>> Test().dispatch("me")
Nested Action
>>> Test().dispatch("say")
Nested Say
有关如何解决这个问题的任何建议吗?
答案 0 :(得分:4)
我可能会这样做:
def register(dict_, *names):
def dec(f):
m_name = f.__name__
for name in names:
dict_[name] = m_name
return f
return dec
class Test(object):
commands = {}
@register(commands, 'foo', 'fu', 'fOo')
def _handle_foo(self):
print 'foo'
@register(commands, 'bar', 'BaR', 'bAR')
def _do_bar(self):
print 'bar'
def dispatch(self, cmd):
try:
return getattr(self, self.commands[cmd])()
except (KeyError, AttributeError):
# Command doesn't exist. Handle it somehow if you want to
# The AttributeError should actually never occur unless a method gets
# deleted from the class
现在,该类公开了一个dict
,其键是用于测试成员资格的命令。所有方法和字典只创建一次。
t = Test()
if 'foo' in t.commands:
t.dispatch('foo')
for cmd in t.commands:
# Obviously this will call each method with multiple commands dispatched to it once
# for each command
t.dispatch(cmd)
等
答案 1 :(得分:2)
class Test(object):
def dispatch(self):
def say():
print "Nested Say"
def action():
print "Nested Action"
funcs = {
"me" : action,
"action": action,
"say" : say,
"shout" : say
}
Test.funcs.get(cmd, say)()
或者,保持目前的结构:
class Test(object):
funcs = {
"me" : "action",
"action": "action",
"say" : "say",
"shout" : "say"
}
def dispatch(self, cmd):
def say():
print "Nested Say"
def action():
print "Nested Action"
locals()[Test.funcs.get(cmd, "say")]()
但是,我觉得这个设计有点奇怪。为什么类级别的dict应该知道dispatch的本地函数?