我在SQL表中有一个列,其中一些值是分隔的bij "
。
此字符串中的某些值是重复的,我想删除它们。以下是我的数据示例:
---------------
| qw"qw"er"er |
---------------
| q"w"w"q |
---------------
| f"k"s"g |
---------------
现在结果应该替换任何重复项:
---------------
| qw"er |
---------------
| q"w" |
---------------
| f"k"s"g |
---------------
首先,我想拆分字符串,然后删除重复项。任何人都可以帮我解决这个问题吗?
答案 0 :(得分:4)
具有解析功能的选项1
Declare @YourTable table (ID int,YourCol varchar(50))
Insert Into @YourTable values
(1,'qw"qw"er"er'),
(2,'q"w"w"q'),
(3,'f"k"s"g')
Select A.ID
,A.YourCol
,DeDuped = Stuff((Select '"' + RetVal
From (Select RetSeq=Min(RetSeq),RetVal
From [dbo].[udf-Str-Parse](A.YourCol,'"')
Group By RetVal) P
Order by 1 For XML Path('')),1,1,'')
From @YourTable A
<强>返回强>
ID YourCol DeDuped
1 qw"qw"er"er qw"er
2 q"w"w"q q"w
3 f"k"s"g f"k"s"g
选项2:没有解析功能
Declare @YourTable table (ID int,YourCol varchar(50))
Insert Into @YourTable values
(1,'qw"qw"er"er'),
(2,'q"w"w"q'),
(3,'f"k"s"g')
Select A.ID
,A.YourCol
,DeDuped = Stuff((Select '"' + RetVal
From (Select RetSeq=Min(RetSeq),RetVal
From (
Select RetSeq = Row_Number() over (Order By (Select null))
,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
From (Select x = Cast('<x>' + replace((Select replace(A.YourCol,'"','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A
Cross Apply x.nodes('x') AS B(i)
) P1
Group By RetVal) P
Order by RetSeq
For XML Path('')),1,1,'')
From @YourTable A
<强>返回强>
ID YourCol DeDuped
1 qw"qw"er"er qw"er
2 q"w"w"q q"w
3 f"k"s"g f"k"s"g
感兴趣的UDF
CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table
As
Return (
Select RetSeq = Row_Number() over (Order By (Select null))
,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
From (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A
Cross Apply x.nodes('x') AS B(i)
);
--Thanks Shnugo for making this XML safe
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')
--Performance On a 5,000 random sample -8K 77.8ms, -1M 79ms (+1.16), -- 91.66ms (+13.8)