使用2个不同的* ngFor填充表格

时间:2017-03-11 16:45:32

标签: angular html-table ngfor

下面是我的JSON对象数组:

{
  "tagFrequency": [
    {
      "value": "aenean",
      "count": 1,
      "tagId": 251
    },
    {
      "value": "At",
      "count": 1,
      "tagId": 249
    },
    {
      "value": "faucibus",
      "count": 1,
      "tagId": 251
    },
    {
      "value": "ipsum",
      "count": 1,
      "tagId": 251
    },
    {
      "value": "lobortis",
      "count": 1,
      "tagId": 194
    },
    {
      "value": "molestie",
      "count": 1,
      "tagId": 251
    },
    {
      "value": "unde tempor, interdum ut orci metus vel morbi lorem. Et arcu sed wisi urna sit egestas fringilla, at erat. Dolor nunc.",
      "count": 1,
      "tagId": 199
    },
    {
      "value": "Vestibulum",
      "count": 1,
      "tagId": 251
    }
  ]
}

我想显示这些属性即。表中的value,count和tagName(使用tagId获取)。对于我使用ngFor的前两个属性。但是,我想打印tagName,我正在使用tagId并将其存储在tagNames数组中。以下是我的组件代码:

frequencies: any;
tagNames: string[] = [];

ngOnInit() {
    if (this.route.snapshot.url[0].path === 'tag-frequency') {
      let topicId = +this.route.snapshot.params['id'];

      this.tagService.getTagFrequency(topicId)
        .then(
            (response: any) => {
          this.frequencies = response.json().tagFrequency
          for(let tagFrequency of this.frequencies) {
            this.getTagName(tagFrequency.tagId)
          }
        }
        )
        .catch(
            (error: any) => console.error(error)
        )
    }
}

  getTagName(tagId: number): string {
    return this.tagService.getTag(tagId)
    .then(
        (response: any) => {
          this.tagNames.push(response.name)
        }
    )
    .catch(
      (error: any) => {
        console.error(error)
      }
    )
  }

这就是我尝试在UI上打印它们的方式:

<table>
  <thead>
    <tr>
      <th>{{ 'word' }}</th>
      <th>{{ 'tag-name' }}</th>
      <th>{{ 'frequency' }}</th>
      <th></th>
    </tr>
  </thead>
  <tbody>
      <ng-container *ngFor="let name of tagNames">
        <tr *ngFor="let frequency of frequencies; let i=index">
          <td>{{ frequency.value }}</td>
          <td>{{ name }}</td>
          <td>{{ frequency.count }}</td>
        </tr>
      </ng-container>
  </tbody>
</table>

但我在列tag-name下得到[object object]。有人可以帮我解决这个问题吗?

我尝试使用上面的ng-container,但结果在UI上看起来像这样: tag-name-issue

哪个错了。我只需要前3行,标记名称分别为“Subtag 3”,“Zeit1”,“Tag 1”,分别为1,2,3行。

提前致谢。

2 个答案:

答案 0 :(得分:3)

你不能在一个元素上加倍*ngFor。您可以使用辅助元素<ng-container>,如

  <tr *ngFor="let frequency of frequencies; let i=index">
    <ng-container *ngFor="let name of tagNames">
      <td>{{ frequency.value }}</td>
      <td>{{ name }}</td>
      <td>{{ frequency.count }}</td>
    </ng-container>
  </tr>

答案 1 :(得分:3)

您可以使用索引变量,迭代* ngFor中的频率数组并将其索引用于tagNames

<tr *ngFor="let frequency of frequencies; let i=index">
      <td>{{ frequency.value }}</td>
      <td>{{ tagNames[i] }}</td>
      <td>{{ frequency.count }}</td>
  </tr>

确保已初始化tagNames:

tagNames:string [] = [];