我使用的是Laravel 5.4和MySql 5.7,PHP 5.6。 我试图调用一个存储过程(执行SELECT查询,连接多个表),并将结果返回给我的PHP。
以下是我尝试失败的事情:
PHP 1:
$result = DB::select('CALL rentalsAvailables_get(?, ?, ?, ?)',
array(
'p0' => Carbon::now(),
'p1' => Carbon::now()->addDays(7),
'p2' => 100,
'p3' => 2
)
);
return var_dump($result);
结果1:
{
"error": {
"message": "SQLSTATE[HY000]: General error: 2031 (SQL: CALL rentalsAvailables_get(2017-03-11 16:00:42, 2017-03-18 16:00:42, 100, 2))",
"code": "HY000",
"status_code": 500
}
}
PHP 2:
$result = DB::select('CALL rentalsAvailables_get(:p0, :p1, :p2, :p3)',
array(
'p0' => Carbon::now(),
'p1' => Carbon::now()->addDays(7),
'p2' => 100,
'p3' => 2
)
);
return var_dump($result);
结果2:
array(0) {
}
**存储过程:**
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `rentalsAvailables_get`(IN `startDate` DATETIME, IN `endDate` DATETIME, IN `maxPrice` INT(11) ZEROFILL, IN `capacity` INT(2))
NO SQL
SELECT a.rentalId, a.rentalName, a.rentalBathroom, a.rentalBedroom, a.rentalCapacity, a.rentalCover, a.rentalLat, a.rentalLong, a.rentalLocation, a.rentalStatus, a.rentalSummary, a.rentalText, a.rentalOwnerId,
b.rentalTypeId, b.rentalTypeName,
c.id as 'userId', c.name,
d.rentalPriceId, d.rentalPrice
FROM rentals as a
INNER JOIN rentalTypes as b
ON a.rentalTypeId = b.rentalTypeId
INNER JOIN users as c
ON a.rentalOwnerId = c.id
INNER JOIN rentalprice as d
ON a.rentalId = d.rentalId
WHERE a.rentalCapacity > @p3
AND a.rentalStatus = true
AND d.rentalPrice < @p2
AND d.rentalPriceStartDate <= @p0
AND d.rentalPriceEndDate >= @p1
AND a.rentalId NOT IN (
SELECT eSub.rentalId FROM unavailabilities as eSub WHERE eSub.unavailabilityStartDate >= @p0 AND eSub.unavailabilityEndDate <= @p1
)
AND a.rentalId NOT IN (
SELECT fSub.rentalId FROM rent as fSub WHERE fSub.rentStartDate >= @p0 AND fSub.rentEndDate <= @p1
)$$
DELIMITER ;
注意:
我当然已经检查过了,当我这样调用它时,我的查询得到结果:
SET @p0='2017-03-11 04:26:09.000000';
SET @p1='2017-03-17 04:26:09.000000';
SET @p2='1000';
SET @p3='2';
CALL `rentalsAvailables_get`(@p0, @p1, @p2, @p3);
有没有人已经遇到过这个问题? 感谢您的阅读
答案 0 :(得分:1)
您应该将CALL your_procedure
通过DB::raw
传递给DB::SELECT
。
所以这将起作用并返回结果集:
$p0 = Carbon::now();
$p1 = Carbon::now()->addDays(7);
$p2 = 100;
$p3 = 2;
DB::select(DB::raw("CALL rentalsAvailables_get($p0, $p1, $p2, $p3)"));
您也可以使用hydrate
方法将结果集转换为 Eloquent model 。
Foo::hydrate($result_from_db_select);
希望这可以帮助你6个月后:))
答案 1 :(得分:0)
你看到这两个值
2017-03-11 16:00:42, 2017-03-18 16:00:42//they are not escaped that's your problem
解决方案 -
$result = \DB::statement('CALL rentalsAvailables_get(\'' . Carbon::now() . '\', \'' . Carbon::now()->addDays(7) . '\', 100, 2)')->fetchAll();
答案 2 :(得分:0)
$result = DB::select('CALL rentalsAvailables_get(?, ?, ?, ?)',
array(
'p0' => Carbon::now(),
'p1' => Carbon::now()->addDays(7),
'p2' => 100,
'p3' => 2
)
);
上面的是通过索引绑定param =&GT;只需要下面就足够了
$result = DB::select('CALL rentalsAvailables_get(?, ?, ?, ?)',
array(
Carbon::now(),
Carbon::now()->addDays(7),
100,
2
)
);
请阅读有关PHP PDO的更多信息