Question

我正在尝试在AgreementLineQuantityCommitment中插入新行，并将它们插入到表中但不以表格形式出现，代码为：有什么建议吗？

LineqtyComm.initValue();
            select  firstOnly LineqtyComm where LineqtyComm.Agreement == _aggrHeader.RecId;

            LineqtyComm.initFromAgreementHeader(_aggrHeader);
            LineqtyComm.ItemId = _itemId;
            LineqtyComm.CommitedQuantity = _qty;
            LineqtyComm.ProductUnitOfMeasure = _unitOfMeasure;
            LineqtyComm.PriceUnit = _PriceUnit;
            LineqtyComm.ExpirationDate = _expirationDate;

            inventDimLoc   = LineqtyComm.inventDim();
            inventDimLoc.InventSiteId = _SiteId;
            inventDimLoc.InventLocationId = _locationId;
            inventDimLoc.wMSLocationId = _whId;
            inventDim = InventDim::findOrCreate(inventDimLoc);
            LineqtyComm.inventDimId = inventDim.inventDimId;
            LineqtyComm.LineNumber  = AgreementLine::lastLineNum(_aggrHeader.RecId) + 1.0;

            LineqtyComm.initFromInventTable();
            LineqtyComm.insert();

Answer 1

1）请更改以下代码行。由于这行代码LineqtyComm使用退出记录值进行初始化，但在记录未退出时不会发生。 LineqtyComm.initValue（）;行初始化总是被覆盖。

LineqtyComm.initValue();

select  firstOnly LineqtyComm where LineqtyComm.Agreement == _aggrHeader.RecId;

到

select  firstOnly LineqtyComm where LineqtyComm.Agreement == _aggrHeader.RecId;
if (!LineqtyComm.Recid)
{
    LineqtyComm.initValue();
}

2）然后改变下面的行

inventDimLoc   = LineqtyComm.inventDim();

到

inventDimLoc.clear();

当你创建像InventDim :: findOrCreate（inventDimLoc）;这样的inventdim时，最好清除而不是获取现有的inventdim行。

插入在AgreementLineQuantityCommitment中的记录不会出现在Form ax 2012中

1 个答案: