所以对于我来说,我应该制作一个猜谜游戏,在你接近答案的时候给你提供线索。我的问题是,当我运行它并且我得到一个数字正确时,我显然会保留该数字并继续使用其他4个数字,当我这样做时,问题是我的正确数字计数器不断上升,即使我没有'得到其他数字正确..我该如何解决这个问题?我是否能够在每个if语句中添加中断,还是会完全退出我的do while循环?
public class GuessingGame {
public static void main(String[] args) {
int guess,numDigitsCorrect=0,sumDigitsCorrect=0,attempts=0,answer;
Random rng = new Random();
Scanner consoleScanner = new Scanner(System.in);
answer = rng.nextInt(90000) + 10000;
System.out.println("I have randomly chosen a 5-digit code for you to guess.Each time you guess,\n"
+ "I will tell you how many digits are correct and the sum of the digits that are correct."
+ "For example, if the number is \"68420\" and you guess 12468, I will respond:\n"
+ "Number of Digits Correct: 1\n"
+ "Sum of Digits Correct: 4\n"
+ "From deduction, you will know the 4 was correct in the guess."
+ "\nNow its your turn..................................................................");
do{
System.out.print("Please enter a 5-digit code (your guess): ");
guess = consoleScanner.nextInt();
int g1 = guess/10000;
int g2 = guess%10000/1000;
int g3 = guess % 10000 % 1000 / 100;
int g4 = guess % 10000 % 100 /10;
int g5 = guess % 10000 % 10 / 1;
int a1 = answer/10000;
int a2 = answer%10000/1000;
int a3 = answer % 10000 % 1000 / 100;
int a4 = answer % 10000 / 100 / 10;
int a5 = answer % 10000 % 10 / 10;
if(g1 == a1)
{
numDigitsCorrect ++;
sumDigitsCorrect += a1;
System.out.println("\nNumber of digits correct: " + numDigitsCorrect) ;
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
System.out.println();
}
if(g2 == a2)
{
numDigitsCorrect ++;
sumDigitsCorrect += a2;
System.out.println("Number of digits correct: " + numDigitsCorrect) ;
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
System.out.println();
}
if (g3 == a3)
{
numDigitsCorrect ++;
sumDigitsCorrect += a3;
System.out.println("Number of digits correct: " + numDigitsCorrect) ;
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
System.out.println();
}
if (g4 == a4)
{
numDigitsCorrect ++;
sumDigitsCorrect += a4;
System.out.println("Number of digits correct: " + numDigitsCorrect) ;
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
System.out.println();
}
if (g5 == a5)
{
numDigitsCorrect ++;
sumDigitsCorrect += a5;
System.out.println("Number of digits correct: " + numDigitsCorrect) ;
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
System.out.println();
}
if(guess == answer)
{
System.out.println("****HOORAY! You solved it. You are so smart****");
break;
}
}while (guess != answer);
}
}
答案 0 :(得分:1)
很难解决的问题 -
确保a4
,a5
正确
int a4 = answer % 10000 % 100 / 10; // note the modulus
int a5 = answer % 10000 % 10; // note divided by 1 or remove the redundant statement
如果在if
区域内,则将您的打印语句从do
块移出到所有区域的末尾 -
if (g1 == a1) {
numDigitsCorrect++;
sumDigitsCorrect += a1;
}
... //other if statements
if (guess == answer) {
System.out.println("****HOORAY! You solved it. You are so smart****");
break;
}
System.out.println("Number of digits correct: " + numDigitsCorrect);
System.out.println("Sum of digits correct: " + sumDigitsCorrect);
此外,您已经进行了检查
if (guess == answer) {
System.out.println("****HOORAY! You solved it. You are so smart****");
break;
}
在您的do
中,您可以将您的状态更改为true
-
do {
... your existing code
} while(true);
回答
我是否可以在每个if语句中添加中断
如果这样做,即使是一位数匹配,你的循环也会退出(中断)。
重要的是要修复计数器,将do块中的计数器初始化为
do {
numDigitsCorrect = 0;
sumDigitsCorrect = 0;
.. // existing logic
}