Question

我有一系列变量在下一个循环中收集。我想将它们存储在一个数组中，以便稍后我可以在一些javascript中访问它们，所以我设置了

$remainingTime = array();

之前（！$ listing-＆gt; EOF）{

填充变量后，我添加了

$remainingTime[] = array( $remainingDay, $remainingHour, $remainingMinutes, $remainingSeconds );

如果我这样做

echo "<pre>";
print_r($remainingTime);
echo "</pre>";

循环结束后，我得到以下输出

Array
(
[0] => Array
    (
        [0] => 6
        [1] => 14
        [2] => 34
        [3] => 1
    )

)
Array
(
[0] => Array
    (
        [0] => 6
        [1] => 14
        [2] => 34
        [3] => 1
    )

[1] => Array
    (
        [0] => 5
        [1] => 15
        [2] => 33
        [3] => 12
    )

)
Array
(
[0] => Array
    (
        [0] => 6
        [1] => 14
        [2] => 34
        [3] => 1
    )

[1] => Array
    (
        [0] => 5
        [1] => 15
        [2] => 33
        [3] => 12
    )

[2] => Array
    (
        [0] => 8
        [1] => 16
        [2] => 4
        [3] => 33
    )

)
Array
(
[0] => Array
    (
        [0] => 6
        [1] => 14
        [2] => 34
        [3] => 1
    )

[1] => Array
    (
        [0] => 5
        [1] => 15
        [2] => 33
        [3] => 12
    )

[2] => Array
    (
        [0] => 8
        [1] => 16
        [2] => 4
        [3] => 33
    )

[3] => Array
    (
        [0] => 2
        [1] => 5
        [2] => 38
        [3] => 17
    )

)

因此，它似乎每次进行循环时都在构建一个新数组，而不是仅仅添加下一个数据集。

构建数组我在哪里出错了？

Answer 1

您使用的赋值语法（$ remainingTime []）将您指定的值作为新元素推送到数组中。不使用方括号就试一试。

循环中的数组数据不正确

1 个答案: