未发送Symfony cookie(但在响应标头中)

时间:2017-03-10 16:58:39

标签: php cookies symfony

我无法理解为什么我的cookie没有被发送。 我已经检查了所有关于它的线程,似乎我做得对。 我在Symfony调试中看不到cookie,但在我的浏览器上看不到。

    public function indexAction(Request $request)
{


    $response = new Response();
    $userID = $request->cookies->get('myCookie123');

    if (empty($userID)) {

        $uniqueID = $this->generateIDUtil();
        $response->headers->setCookie(new Cookie('myCookie123', $uniqueID, 2147483647));
        $response->sendHeaders();

    }else{
        var_dump('USER ALREADY KNOW <br>' );
    }

    var_dump($response->headers->getCookies()); //GIVES CORRECT COOKIE OBJECT
    var_dump('<br>');
    var_dump($request->cookies->all()); //GIVES ONLY PHPSESSID, BUT NOT THE ONE CREATED
    var_dump('<br>');
    var_dump($request->cookies->get('myCookie123')); //GIVES NULL


    return $response->setContent($this->render('MyBundle:Core:index.html.twig'));
}

enter image description here

2 个答案:

答案 0 :(得分:4)

所以这里有一个代码,适用于想要从cookie获取userId的任何人。使用所有use语句和twig渲染模板。

上述解决方案的问题在于,在发送标题时不会渲染视图时会显示空白页。

由于记录非常严重,这是一个有效的解决方案。

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Cookie;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;

class tempController extends Controller
{
    public function indexAction(Request $request)
    {

        $user = $request->cookies->get('myCookie'); // $user is a string (the userID) or null if there is no cookie.

        if (!empty($user)) {  
            //Fetch user data in the DB
        }

        // some code ... 


        $response = new Response();

        if ($user instanceof User) {
            // do some stuff like pre fill a form
        }else{
            // We don't know the user we send a cookie.
            $cookie = new Cookie('myCookie', $this->generateIDUtil(), time() + (365 * 24 * 60 * 60));  // Expires 1 years
            $response->headers->setCookie($cookie);
            $response->sendHeaders();
        }

        //Render the view  WITH the response (It's very important to put $response as 3rd parameter)
        return $this->render('MyBundle:Core:index.html.twig', array(/* view param */), $response);
    }
}

答案 1 :(得分:2)

以下是正确创建Cookie并将其作为响应发送给客户的方法:

$res = new Response();
$cookie = new Cookie(
        'my_cookie',
        $student->getStuId(),
        time() + ( 2 * 365 * 24 * 60 * 60)  // Expires 2 years.
);
$res->headers->setCookie( $cookie );
$res->send();

我一直都在使用它,所以如果你还有问题,请告诉我们。