Question

如果滚动到页面底部，如何从数组中加载更多内容。所以只有前5个＆＃34;项目＆＃34;如果显示，如果您滚动到底部，则会显示下5个，因此浏览器不会崩溃。我的阵列：

$statement = $pdo->prepare("SELECT * FROM actvt");
$statement->execute();
$users = $statement->fetchAll();

foreach($users as $row) { 
echo $row("username");
}

Answer 1

PHP

function callMore(){
 $last_appt = $_POST['last_result'];
 $statement = $pdo->prepare("SELECT * FROM actvt WHERE date = ".$last_appt." limit = X "); //not sure your table structure , X is how many you want to load
 foreach($statement as $val){
  //Set your gathered results here
 }
 return X //return the results to your ajax call
}

js / ajax call

$.ajax({
            type: 'POST',
            data: {
                action: 'callMore',
                lastPost : XXXX //Put your last post here
            },
            success : function(msg){
                //Do something with returned data append where ever
            },
            datatype: 'json',
   });

从这里你需要检测你何时到达最后一篇文章...我建议你检测你何时在页面底部，如果你在最后一篇文章中使用jquery使用scrollTop，那就找它的Y值，然后窗口偏移量，滚动触发，如果你接近底部，则触发。你已经到达底部，运行你的ajax函数并检索下一个结果。

Answer 2

所以你可以像load.php一样创建......

$start=$_GET["page"]*100;//100 entries
$statement = $pdo->prepare("SELECT * FROM actvt ");
$statement->execute();
$users = $statement->fetchAll();
$counter=0;
foreach($users as $row) { 
$counter++;
if($counter>$start && $counter <=$start+100){//100 entries
echo $row("username");
}
}
if($counter<$row.length){
echo "<a href='?page=".($page+1)."'>Next Page</a>";
}

现在你可以打电话给“http://yourpage?page=10”......

js部分足以填补另一个答案......

从Php阵列加载更多

2 个答案: