Question

SELECT a.OCD, a.[f_name],a.[l_name],a.[ads_phone], b.wk1m, b.wk1t, b.wk1w, b.wk1r, b.wk1f, b.wk2m, b.wk2t, b.wk2w, b.wk2r, b.wk2f
FROM [dbo].[tbl_teleworkers] as a
inner join [dbo].[tbl_scheduled] as b ON  a.pin = b.pin
where ocd = '022'

这是我的结果：

OCD|f_name|l_name|ads_phone|wk1m|wk1t|wk1w|wk1r|wk1f|wk2m|wk2t|wk2w|wk2r|wk2f
022|John  |smith |111-1111 |M   |    |    | R  |    |    |    |    |    |
022|Jane  |smith |222-2222 |    |    |    | R  |    |    |    |  W |    |
022|Joe   |smith |333-3333 |M   |    |    |    |  F |    |    |    |    |
022|Jim   |smith |444-4444 |    | T  |    |    |    | M  |    |    |    |
022|Jill  |smith |555-5555 |M   |    | W  |    |    |    |    |    |  R |

以下是我想要得到的内容：因此，我试图展示星期一出现的所有星期一人，而不是一周的字母。像这样......

wk1m |wk1t |wk1w |wk1r |wk1f |wk2m |wk2t|wk2w  |wk2r |wk2f
John |Jim  |Jill |John |Joe  |Jim  |    |Jane  |Jill |
phone|phone|phone|phone|phone|phone|    |Phone |phone|
Joe  |     |     |Jane |     |     |    |      |     |
Phone|     |     |phone|     |     |    |      |     |
Jill |     |
Phone|     |

这是我到目前为止所尝试的内容：

SELECT *
FROM 
(
 SELECT 
 ROW_NUMBER() OVER(ORDER BY f_name ASC) AS Row, f_name,
        CASE    WHEN b.wk1m != '' then f_name + ' ' + l_name END as first,
        CASE    WHEN b.wk1t != '' then f_name + ' ' + l_name END as wk1t,
        CASE    WHEN b.wk1w != '' then f_name + ' ' + l_name END as wk1w,
        CASE    WHEN b.wk1r != '' then f_name + ' ' + l_name END as wk1r,
        CASE    WHEN b.wk1f != '' then f_name + ' ' + l_name  END as wk1f,
    CASE    WHEN b.wk2m != '' then f_name + ' ' + l_name  END as wk2m,
    CASE    WHEN b.wk2t != '' then f_name + ' ' + l_name  END as wk2t,
    CASE    WHEN b.wk2w != '' then f_name + ' ' + l_name  END as wk2w,
    CASE    WHEN b.wk2r != '' then f_name + ' ' + l_name  END as wk2r,
    CASE    WHEN b.wk2f != '' then f_name + ' ' + l_name  END as wk2f        
    FROM [dbo].[tbl_teleworkers] as a
    inner join [dbo].[tbl_scheduled] as b ON  a.pin = b.pin
    where ocd = '165'
) as S
PIVOT
(
MAX (row) FOR f_name in ([wk1m])
) as PivotTable;

非常感谢任何帮助。谢谢！

Answer 1

请尝试这个并让我知道它是否有效

SELECT 
wk1m = CASE WHEN ISNULL(b.wk1m,'')<>''
                THEN a.[f_name] 
            ELSE '' END, 
wk1t = CASE WHEN ISNULL(b.wk1t,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk1w = CASE WHEN ISNULL(b.wk1w,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk1r = CASE WHEN ISNULL(b.wk1r,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk1f = CASE WHEN ISNULL(b.wk1f,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk2m = CASE WHEN ISNULL(b.wk2m,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk2t = CASE WHEN ISNULL(b.wk2t,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk2w = CASE WHEN ISNULL(b.wk2w,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk2r = CASE WHEN ISNULL(b.wk2r,'')<>''
                THEN a.[f_name] 
            ELSE '' END,
wk2f = CASE WHEN ISNULL(b.wk2f,'')<>''
                THEN a.[f_name] 
            ELSE '' END
FROM [dbo].[tbl_teleworkers] as a
      inner join [dbo].[tbl_scheduled] as b 
         ON  a.pin = b.pin
where ocd = '022'

我试图在桌子/日历上显示名称，不确定SQL Pivot是否有效

1 个答案: