在SQL Server 2012中，当组内的值不同时求和

Question

当Manager的B_Allocation值不明显时，我想对不同的值求和。例如，对于Manager 5，我希望能够总计10800,661782.60,2141987.20和2163743.43。对于像B_Allocation不同的6,8和14这样的经理人，我希望下面显示的值（Original Image）

select
          BU.BuCode
        , PE.ManagerID
        , BUA.AllocatedAmount as B_Allocation
        , PE.AllocatedAmount
    from CFMS_ProjectEntry PE
    join CFMS_BUAllocation BUA on BUA.BUDGETENTRYID = PE.BUDGETENTRYID
    join CFMS_BU           BU  on BU.BUID           = BUA.BUID
    join CFMS_User         US  on US.UserID         = PE.ManagerID
    where BUCODE = 42406016
    group by  BU.BUCode
            , ManagerID
            , BUA.AllocatedAmount
            , PE.AllocatedAmount

我想要的（Original Image）：

+ -------- + --------- + ------------ + --------------- +
| BUCode   | ManagerID | B_Allocation | AllocatedAmount |
+ -------- + --------- + ------------ + --------------- +
| 42406016 | 5         | 10800.00     | 1293916.30      |
| 42406016 | 5         | 661782.60    | 1723699.70      |
| 42406016 | 5         | 2141987.20   | 4628466.40      |
| 42406016 | 5         | 2163743.43   | 109956.12       |
| 42406016 | 5         | 2163743.43   | 407655.00       |
| 42406016 | 5         | 2163743.43   | 499902.00       |
| 42406016 | 5         | 2163743.43   | 523275.55       |
| 42406016 | 5         | 2163743.43   | 622954.76       |
| 42406016 | 6         | 4747880.45   | 1500000.00      |
| 42406016 | 6         | 4747880.45   | 2000000.00      |
| 42406016 | 8         | 726893.75    | 14142.71        |
| 42406016 | 8         | 726893.75    | 22143.56        |
| 42406016 | 8         | 726893.75    | 106448.50       |
| 42406016 | 8         | 726893.75    | 265501.45       |
| 42406016 | 8         | 726893.75    | 318657.53       |
| 42406016 | 14        | 4747880.45   | 747880.45       |
+ -------- + --------- + ------------ + --------------- +

Answer 1

试试这个：

$nextpage = $paged + 1;
echo "<button id='btn1' value=$nextpage>Load even more </button>";