我有一个像这样的布尔数组
bool_arr = [True, True, False]
我想将两个字符串映射到每个布尔值
string_arr = ['r', 'r, 'k']
我如何使用numpy来映射?
答案 0 :(得分:2)
7374 extra bytes at beginning or within zipfile
(attempting to process anyway)
inflating: META-INF/MANIFEST.MF
Manifest-Version: 1.0
Implementation-Title: TEST
Implementation-Version: 0.0.1
Archiver-Version: Plexus Archiver
Built-By: prasathm
Implementation-Vendor-Id: TEST
Spring-Boot-Version: 1.4.2.RELEASE
Implementation-Vendor: Pivotal Software, Inc.
Main-Class: org.springframework.boot.loader.WarLauncher
Start-Class: com.mytest.Application
Spring-Boot-Classes: WEB-INF/classes/
Spring-Boot-Lib: WEB-INF/lib/
Created-By: Apache Maven 3.3.9
Build-Jdk: 1.8.0_25
Implementation-URL: http://projects.spring.io/spring-boot/TEST/
答案 1 :(得分:2)
使用索引的矢量化方法 -
bool_arr = np.array([True, True, False]) # Input boolean array
strings = np.array(['k','r']) # Input array of strings for mapping
out = np.take(strings, bool_arr)
out = np.take(strings, bool_arr.astype(int))
out = strings[bool_arr.astype(int)]
如果我们只需要在两个字符串之间进行选择,请使用np.where
-
np.where(bool_arr, 'r','k')
答案 2 :(得分:2)
您可以使用<!--template bindings={
"ng-reflect-ng-for-of": null
}-->
方法:
<ul class="listboxtickets">
<li class="selectlistticket" *ngFor="let tick of ticketlists">
<div class="atickid"> {{tick.id}} </div>
<div class="atickname"> {{tick.summary}} </div>
<div class="atickstat"> <img class="staraimg" src="assets/images/star_icon.png"/> </div>
<div class="namelinet"> <img src="assets/images/text_bottomline.png"/> </div>
</li>
</ul>
给出:
numpy.vectorize