Question

我已经实现了单击和双击。但每当我双击屏幕时，也会运行单击代码。请参阅以下代码：

    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    let touch = touches.first as UITouch!
    let touchLocation = touch?.location(in: self) 
    let touchedNode = self.atPoint(touchLocation!)

if touch?.tapCount == 1 {
        print("single tap")
        if let name = touchedNode.name        {
            if name == "enemySprite"
            {
                //handle single Tap
             }
         }
    }

if touch?.tapCount == 2 {
        print("double tap")
        if let name = touchedNode.name        {
            if name == "enemySprite"
            {
                //handle double Tap
             }
         }
    }
}

如何使每个分接计数互斥？

更新

根据Apurv的回答和Whirlwind的评论，我认为以下代码显示有效。

 override func didMove(to view: SKView) {

    var tapGesture = UITapGestureRecognizer(target: self, action: #selector(self.view.sampleTapGestureTapped(recognizerMethod:)))
    self.view.addGestureRecognizer(tapGesture!)
    tapGesture.numberOfTapsRequired = 1;

    var tapGestureDouble = UITapGestureRecognizer(target: self, action: #selector(self.view.sampleTapGestureTapped(recognizerMethod2:)))
    self.view.addGestureRecognizer(tapGestureDouble!)
    tapGestureDouble.numberOfTapsRequired = 2;

    [tapGesture requireGestureRecognizerToFail : tapGestureDouble];

}

它不起作用，我说错误，

Value of type ’SKView?’ has no member ‘sampleTapGestureTapped(recognizerMethod:)’ and 
Value of type ’SKView?’ has no member ‘sampleTapGestureTapped(recognizerMethod2:)’

指向点击手势变量的声明

另外，我收到了错误

Expected expression in the container literal

指向上述方法的最后一行。

我想我在这里错过了一些东西，我真的很感激对此的一些帮助和澄清。

Answer 1

您不必访问ViewController ...您可以在场景中处理点击，如下所示：

import SpriteKit

class GameScene: SKScene {

    var recognizers:[UIGestureRecognizer] = []

    override func didMove(to view: SKView) {

        // Get label node from scene and store it for use later


        let single = UITapGestureRecognizer(target: self, action: #selector(GameScene.singleTapHandler(recognizer:)))
        view.addGestureRecognizer(single)
        single.numberOfTapsRequired = 1
        recognizers.append(single)

        let double = UITapGestureRecognizer(target: self, action: #selector(GameScene.doubleTapHandler(recognizer:)))
        view.addGestureRecognizer(double)
        double.numberOfTapsRequired = 2
        recognizers.append(double)

        single.require(toFail: double)

    }

    override func willMove(from view: SKView) {
        super.willMove(from: view)

        for recognizer in recognizers {
            self.view?.removeGestureRecognizer(recognizer)
        }
        recognizers.removeAll()
    }

    func singleTapHandler(recognizer:UITapGestureRecognizer){

        print("Single tap detected")
    }

    func doubleTapHandler(recognizer:UITapGestureRecognizer){
        print("Double tap detected")
    }

}

当然，在ViewController上调用一些方法可以通过几种方式完成（例如委托）......但是，根据你的评论，我认为处理当前场景中的点击是你想要的实现。

修改

要回答评论中的问题...您可以通过在视图中查找触摸位置，将其转换为场景中的位置以及抓取该节点来抓取被触摸的节点位置：

func singleTapHandler(recognizer:UITapGestureRecognizer){ print("Single tap detected") let locationInView = recognizer.location(in: self.view) let locationInScene = self.convertPoint(fromView: locationInView) print(locationInScene) let node = atPoint(locationInScene) if let nodeName = node.name { //do stuff } //or if let sprite = node as? SKSpriteNode { // node is an SKSpriteNode } }

Answer 2

处理点按的更好方法是使用手势识别器。使用UITapGestureRecognizer并设置要跟踪的正确数量的点按。

现在允许两个分接头无缝地添加代码，以确保只有在双击失败时才会调用单个手势。请参阅下面的代码。

    var tapGesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.sampleTapGestureTapped(recognizerMethod:)))
    self.view.addGestureRecognizer(tapGesture!)
tapGesture.numberOfTapsRequired = 1;

var tapGestureDouble = UITapGestureRecognizer(target: self, action: #selector(ViewController.sampleTapGestureTapped(recognizerMethod2:)))
    self.view.addGestureRecognizer(tapGestureDouble!)
tapGestureDouble.numberOfTapsRequired = 2;

[tapGesture requireGestureRecognizerToFail:tapGestureDouble];

如何在touchesBegan方法中发生双击时防止单击被调用

2 个答案: